The residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.
<h3>What is residual value?</h3>
The residual value is the estimated value which is calculated for the end of the lease terms for a fixed asset.
Points and their residual values are shown in the table. A 3-column table with 5 rows.
- x 1, 2, 3, 4, 5.
- y 2, 3.5, 5, 6.1, 8.
- Residual Value -0.4, 0.7, -0.2, -0.6 0
The simple regression line can be represented as,

Here α is the constant, β is the slope and <em>e </em>is the residue.
The point which is farthest from the best fit of the line is 3.5. At y=3.5, the value of residue is 0.7.
Thus, the residual value, which is the farthest from the line of best fit for the table which shows points and their residual values, is 0.7.
Learn more about the residual value here;
brainly.com/question/1168961
answer:
x < 44
step-by-step explanation:
- solve this like an equation
<u>3/4x < 33</u>
- in order to solve this we can multiply this with the denominator first to cross out the fraction and be left with a whole number
3/4x < 33
3/4x(4) < 33(4)
3x < 132
x < 44
The car is worth 17,200.
20,000x .14=2800
20,000-2,800=17,200.
The expression which relates the total time taken and the time taken for the trip is [15s + 15(s+2)] / s² + 2s and 2.32 hours respectively.
<em>Travel time = distance ÷ speed </em>
<u>Second half of the trip</u> :
- <em>Distance covered = 15 miles</em>
<u>Time taken for second half of trip</u> :
Time taken = 15 / s
<u>First half of the trip</u> :
- <em>Speed = s + 2 mph </em>
<u>Time taken for first half of trip :</u>
Time taken = 15 / (s+2)
<u>Total time taken :</u>
<em>First half + second half</em>
15/(s+2) + 15/s = [15s + 15(s+2)] / s² + 2s
B)
If s = 12
<em>Substitute s = 12 into the expression</em> :
[15(12) + 15(12+2)] / 12² + 2(12)
[180 + 210] / 144 + 24
390 / 168
= 2.32 hours
Therefore, the total time taken is 2.32 hours.
Learn more : brainly.com/question/18796573
Im Not Sure But Im Thinking 7/10 Wrote As in A Fraction .