Answer:
11, 15, 26, 41, could be an answer
Answer:
23, 25, 27
Step-by-step explanation:
It can be convenient to work "consecutive integer" problems by using a variable to represent the middle one.
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<h3>setup</h3>
Let x represent the middle integer. Then (x-2) is the first of the three odd integers, and (x+2) is the third. The given relation is ...
2(x -2) +3x = 67 +2(x +2)
<h3>solution</h3>
5x -4 = 2x +71 . . . . . simplify
3x = 75 . . . . . . . . add 4-2x
x = 25 . . . . . . . divide by 3
The three integers are 23, 25, 27.
Answer:
3(×+5)=3 . x+5
Step-by-step explanation:
3(x+5)=3x+15
3 . x+5=3x+15
3 (x+5)=3 . x+5
<u>Start from 7, then add 5 each time.</u>
a7 is 7 plus 30, or <u>37.</u>
Answer:
I think that the probability is 5/4
