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Anon25 [30]
3 years ago
10

I forgot to do slopes

Mathematics
1 answer:
Minchanka [31]3 years ago
7 0
To find the slope of the line, use the rise over run formula:

\frac{y_{2} - y_{1}}{x_{2} - x_{1}}

Take any two points from the line and plug them into the formula.

(0,0) and (10, 5)

\frac{5 - 0}{10 - 0} = \frac{5}{10} = 0.5

The slope of the line is 0.5.

Using the form y = mx, the following equation will be your answer:

y = 0.5x
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Through (-3, 2) parallel to y = -2x-1
Slav-nsk [51]

Answer:

y = - 2x - 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x - 1 ← is in slope- intercept form

with slope m = - 2

Parallel lines have equal slopes , then

y = - 2x + c ← is the partial equation

To find c substitute (- 3, 2 ) into the partial equation

2 = 6 + c ⇒ c = 2 - 6 = - 4

y = - 2x - 4 ← equation of parallel line

3 0
3 years ago
Please help,
VashaNatasha [74]

Answer:

-7.11°F

Step-by-step explanation:

the exchange of gases in the atmosphere

4 0
2 years ago
Full explanation please<br> Will mark brainlist :)
Afina-wow [57]

Answer:B

Step-by-step explanation:

3 0
2 years ago
To which set of numbers does the number belong?
Maslowich
Integers are whole numbers that can be negative or positive. Irrational numbers are numbers with repeating ends while natural numbers are positive whole numbers only. rational numbers are fractions. hence the answer to this problem is D. 
6 0
3 years ago
If a car travels 10 ft due north and then 15 feet due west, how far is the car from it starting point? This is for homework and
krok68 [10]
Answer:

Explanation:

The car travel 10ft north then 15ft due west. In order to find the distance from starting point. We need to find the hypotenuse where the distance to north and west are the adjacent side.

We can use Pythagorean’s theorem according to that:

Let c be the distance from starting point.
And a and b be the distance travel to north and west.

a^2 + b^2 = c^2
10^2 + 15^2 = c^2
100 + 225 = c^2
325 = c^2
Sqrt(325) = c
5sqrt(13) = c

Therefore, the distance from starting point is 5sqrt(13) ft
5 0
3 years ago
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