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Salsk061 [2.6K]
3 years ago
7

Expand and simplify 3(2a+5)+5(a-2)

Mathematics
2 answers:
Wittaler [7]3 years ago
3 0
Step 1 (3* (2a+5)) + 5 *(a-2)
Step 2 <span>3 • (2a + 5) + 5 • (a - 2)
</span>Step 3 final result and your anwser 
11a+5
Hope it helped if it did it that tanks button for me tanks

erastovalidia [21]3 years ago
3 0
3(2a+5)+5(a-2)
6a+15+5a-10
11a+5
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3 /10 4/ 8 which one is bigger?
Olegator [25]

Answer:

4/8

Step-by-step explanation:

3/10 is 0.30 and 4/8 is 0.5

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A recipe for spaghetti sauce requires 4 bottles of ketchup to make 2 gallons. How many bottles of ketchup are needed to make 10
frosja888 [35]

For 10 gallons of sauce, we need 5 times as required for 2 gallons, therefore we need 4 * 5 = 20 bottles of ketchup.

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3 years ago
You are a waterman daily plying the waters of Chesapeake Bay for blue crabs (Callinectes sapidus), the best-tasting crustacean i
notsponge [240]

The question given is incomplete, I googled and got the complete question as below:

You are a waterman daily plying the waters of Chesapeake Bay for blue crabs (Callinectes sapidus), the best-tasting crustacean in the world. Crab populations and commercial catch rates are highly variable, but the fishery is under constant pressure from over-fishing, habitat destruction, and pollution. These days, you tend to pull crab pots containing an average of 2.4 crabs per pot. Given that you are economically challenged as most commercial fishermen are, and have an expensive boat to pay off, you’re always interested in projecting your income for the day. At the end of one day, you calculate that you’ll need 7 legal-sized crabs in your last pot in order to break even for the day. Use these data to address the following questions. Show your work.

a. What is the probability that your last pot will have the necessary 7 crabs?

b. What is the probability that your last pot will be empty?

Answer:

a. Probability = 0.0083

b. Probability = 0.0907

Step-by-step explanation:

This is Poisson distribution with parameter λ=2.4

a)

The probability that your last pot will have the necessary 7 crabs is calculated below:

P(X=7)=  {e-2.4*2.47/7!} = 0.0083

b)

The probability that your last pot will be empty is calculated as:

P(X=0)=  {e-2.4*2.40/0!} = 0.0907

8 0
3 years ago
A Travel Weekly International Air Transport Association survey asked business travelers about the purpose for their most recent
siniylev [52]

Answer:

(a) P (p' > 0.25) = 0.

(b) P (0.15 < p' < 0.20) = 0.7784.

(c) P (133 < X < 171) = 0.2205

Step-by-step explanation:

Let <em>p</em> = proportion of business trip that were for  internal company visit.

It is provided that 19% responded that it was for an internal company visit, i.e.

<em>p</em> = 0.19.

A sample of <em>n</em> = 950 business travelers are randomly selected.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Thus, the distribution of \hat p is N (<em>μ</em> = 0.19, <em>σ </em>= 0.013).

(a)

Compute the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (p' > 0.25) = P (Z > 4.62) = 0

*Use a <em>z</em>-table for the probability.

Thus, the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.

(b)

Compute the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (0.15 < p' < 0.20) = P (-3.08 < Z < 0.77)

                               = P (Z < 0.77) - P (Z < -3.08)

                               = 0.7794 - 0.0010

                               = 0.7784

*Use a <em>z</em>-table for the probability.

Thus, the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.7784.

(c)

Compute the proportion of <em>X</em> = 133  and <em>X</em> = 171 as follows:

p' = 133/950 = 0.14

p' = 171/950 = 0.18

Compute the value of P (0.14 < p' < 0.20) as follows:

P (0.14 < p' < 0.18) = P (-3.85< Z < -0.77)

                               = P (Z < -0.77) - P (Z < -3.85)

                               = 0.2206- 0.0001

                               = 0.2205

*Use a <em>z</em>-table for the probability.

Thus, the probability that between 133 and 171 of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.2205.

7 0
3 years ago
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