6a+16
Explanation:
If there's just a variable, there's an understood 1 in front of it. So what that really says is:
7a-1a+16
So, you combine the a's. 7a minus 1a is 6a. Same as 7-1,but you have a variable stuck on the end of it.
6a+16
:^)
Answer:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
Of the 2809 people who responded to survey, 1634 stated that they currently use social media.
This means that ![n = 2809, \pi = \frac{1634}{2809} = 0.5817](https://tex.z-dn.net/?f=n%20%3D%202809%2C%20%5Cpi%20%3D%20%5Cfrac%7B1634%7D%7B2809%7D%20%3D%200.5817)
98% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.5817%20-%202.327%5Csqrt%7B%5Cfrac%7B0.5817%2A4183%7D%7B2809%7D%7D%20%3D%200.56)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.5817%20%2B%202.327%5Csqrt%7B%5Cfrac%7B0.5817%2A4183%7D%7B2809%7D%7D%20%3D%200.6034)
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
16.92 × 8.4 = 142.128
This is called the product
<u>Answer:</u>
<u>Step-by-step </u><u>Explanation</u><u>:</u>
The sequence is following some rule. And the rule is: Multiplying the term with 4 to get the next term. Like:
Similarly, the next terms are:
The terms are <u>6</u><u>4</u><u>,</u><u> </u><u>2</u><u>5</u><u>6</u><u>,</u><u> </u><u>1</u><u>0</u><u>2</u><u>4</u> which matches with Option D. And that's the correct answer