Volume of reg sq. pyramid = vp
vp = 1/3×s^2×h, where s = side and h = height
Volume of cone = vc =1/3×h×pi×r^2
Now we know that h is the same for both, and the cones diameter = s of square base, so radius (r) = 1/2 s
so now vc = 1/3×h×pi×(1/2s)^2
let's remove the same items for both vc and vp
so 1/3 and h
now let's plug an arbitrary number into each:
vc = pi (10/2)^2 = 3.14×25 = 78.54
vp = s^2 = 10^2 = 100
So any square pyramid has slightly more volume than the cone
Answer:
base=area=1/2b×h
Step-by-step explanation:
it's a pleasure to help you goodbye. if I'm wrong tell me right away.
Answer:
D
Step-by-step explanation:
5n=85
n=17
Answer: Option D

Step-by-step explanation:
For a quadratic function of the form

The x coordinate of the vertice is:

In this case the function is:

So

The x coordinate of the vertice is:

The y coordinate of the vertice is:

The vertice is: (-3, -11)
The form e vertice for a quadratic equation is:

Where
the x coordinate of the vertice is h and the y coordinate of the vertice is k.
Then h=-3 and k =-11
Finally the equation
in vertex form is:
