Given,
SP~QP
SR~QR
In ∆SRP and ∆QRP
SP~QP (given)
SR~QR (given)
PR=PR (common)
Therefore,
∆SRP~∆QRP by SSS congruence rule.
The solid figure is represented by the second option.
Step-by-step explanation:
- The solid figure in the question is a cuboid.
- On opening, it will have 6 faces, each of which will be a rectangle.
- All the corners or edges will have 90° or right angles.
- Also, on opening, one side will have 2 other faces attached to it on top and bottom which is seen in the second figure.
Answer:
pic in explanation
Step-by-step explanation:
It's exponential decay function with y-int (0,3)
I guess the answer of your question is B
The difference between the two graphs is the first one has a steeper line than the second one. hope this helps :)
