We know that
an=[a(n-1)]*2+3
if a7=125
a) Find a1
step 1
find a6
a7=a6*2+3--------> a6=(a7-3)/2-----> a6=(125-3)/2----> a6=61
step 2
find a5
a6=a5*2+3--------> a5=(a6-3)/2-----> a5=(61-3)/2----> a5=29
step 3
find a4
a5=a4*2+3--------> a4=(a5-3)/2-----> a4=(29-3)/2----> a4=13
step 4
find a3
a4=a3*2+3--------> a3=(a4-3)/2-----> a3=(13-3)/2----> a3=5
step 5
find a2
a3=a2*2+3--------> a2=(a3-3)/2-----> a2=(5-3)/2----> a2=1
step 6
find a1
a2=a1*2+3--------> a1=(a2-3)/2-----> a1=(1-3)/2----> a1=-1
the answer is
a1=-1
Answer:
2 + x
2 + (x)
x + (2)
Step-by-step explanation:
Switch them around.
Answer:
0.5 qt
Step-by-step explanation:
Good luck
You will add the two numbers together and add the t as well to make 33t
