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3 years ago

If I want to figure out the DISTANCE covered and I know the SPEED and TIME

Physics

1 answer:

Sergio [31]3 years ago

6 0

Answer:

D=S(t) ................

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Poorly treated municipal wastewater is discharged to a stream. The river flow rate upstream of the discharge point is Qu/s = 8.7

Musya8 [376]

Answer

given,

Q u = 8.7 m³/s

Q d= 0.9 m³/s

BOD concentration = 50 mg/L

a) BOD concentration at the down stream

$C_{down}=\dfrac{0.9\times 50}{8.7+0.9}$

$C_{down}=\dfrac{0.9\times 50}{9.6}$

= 4.69 mg/L

b) discharge = 9.6 m³/s

cross sectional area = 10 m²

velocity steam = $\dfrac{8.7+0.9}{10}$

= 0.96 m/s

time taken to move 50 km down stream = $\dfrac{50 \times 1000}{0.96}$

= 52083.3 s

= $\dfrac{52083.3}{3600\times 24}$

= 0.6 days

now,

$C_t=C_0e^{-kt}$

$C_t=4.6875\ e^{-0.2\times 0.6}$

$C_t = 4.16 mg/L$

5 0

4 years ago

What is the wavelength of a wave that has a speed of 3 km/s and a frequency of 12 Hz

olasank [31]

Answer:

Wavelength = 250 m

Explanation:

[ Refer to the attached file ]

6 0

4 years ago

A transformer has two sets of coils, the primary with N1 = 160 turns and the secondary with N2 = 1400 turns. The input rms volta

vovikov84 [41]

To solve the problem it is necessary to apply the concepts related to the voltage in a coil, through the percentage relationship that exists between the voltage and the number of turns it has.

So things our data are given by

$N_1 = 160$

$N_2 = 1400$

$\Delta V_{1rms} = 62V$

PART A) Since it is a system in equilibrium the relationship between the two transformers would be given by

$\frac{N_1}{N_2} = \frac{\Delta V_{1rms}}{\Delta V_{2rms}}$

So the voltage for transformer 2 would be given by,

$\Delta V_{2rms} = \frac{N_2}{N_1} \Delta V_{1rms}$

PART B) To express the number value we proceed to replace with the previously given values, that is to say

$\Delta V_{2rms} = \frac{N_1}{N_2} \Delta V_{1rms}$

$\Delta V_{2rms} = \frac{1400}{160} 62V$

$\Delta V_{2rms} = 1446.66V$

7 0

3 years ago

How much would a 70.0-kg person weigh on Mercury?

Agata [3.3K]

AS Weight = w =mg

m= 70kg

g on mercury =3.7 m/s²

so W = (70kg) ( 3.7m/s²)

w=259 kgm/s²

w = 259 N

3 0

3 years ago

A pmdc has a stall torque of 10 and maximum mechanical power of 200. What is the maximum angular velocity?

Nadusha1986 [10]

Answer:

The maximum angular velocity is 20 rad/s

Explanation:

Given;

torque, τ = 10 N

maximum mechanical power, P = 200 J/s

The output power of the pmdc is given as;

P = τω

where;

P is the maximum mechanical power

ω is the maximum angular velocity

ω = P / τ

ω = (200) / (10)

ω = 20 rad/s

Therefore, the maximum angular velocity is 20 rad/s

6 0

3 years ago