Answer:
a. 0.8 mW/m² b. 1.6 mW/m² c. 6.4 mW/m²
Explanation:
Intensity,I = P/A were P = power and A = area = 4πr² were r = distance from electric guitar = 5.0 m.
a. When P = 0.25 W, I = 0.25 W/4π5² = 0.25 W/100π = 0.00079 W/m² ≅ 0.0008 W/m² = 0.8 mW/m²
b. When P = 0.50 W, I = 0.50 W/4π5² = 0.50 W/100π = 0.00156 W/m² ≅ 0.0016 W/m² = 1.6 mW/m²
c. When P = 2.0 W, I = 2.0 W/4π5² = 2.0 W/100π = 0.00636 W/m² ≅ 0.0064 W/m² = 6.4 mW/m²
Answer:
option C
Explanation:
given,
energy dissipated by the system to the surrounding = 12 J
Work done on the system = 28 J
change in internal energy of the system
Δ U = Q - W
system losses energy = - 12 J
work done = -28 J
Δ U = Q - W
Δ U = -12 -(-28)
Δ U = 16 J
hence, the correct answer is option C
Answer:
a=2 ok do it and ........
Answer:
C 2000v its obviously ans because if o is 1000 2 vo is 2000v
