Answer:
(a) = 0 N
(b) = 2.4 N
Explanation:
given
box of banana weight = 40.0 N
coefficient of static friction μ = 0.40
coefficient of kinetic friction = 0.20
a). when no horizontal force is applied .
according to Newton 's third law of motion If there is no force applied to the box,so the frictional force exerted is 0 N
b) magnitude of friction force
box and the box is initially at rest
friction force =.Static friction coefficient × weight of the box
friction force = 0.40 × 6
friction force = 2.4 N
The term "unbalanced force" in Newton's first law refers to a force that is not entirely counterbalanced (or cancelled) by the other independent forces. Basically, magnitude can be thought of as simply the "value" or "amount" of any physical quantity. It is a scalar quantity at all times.
Force has both a magnitude and a direction because it is a vector quantity. The amount that encapsulates the force's strength is known as its magnitude.
Consider the following scenario: the force is 10 N in the east. The direction is indicated by "towards east," while the force is indicated by "10."
Unless acted upon by an unbalanced force, an object at rest tends to stay at rest, and an object in motion tends to stay in motion with the same speed and direction.
The term "unbalanced force" in Newton's first law refers to a force that is not entirely counterbalanced (or cancelled) by the other independent forces. An uneven force exists if either all the vertical forces (up and down) or all the horizontal forces do not cancel each other. Looking at the free-body diagram for a particular situation makes it easy to recognize whether an unbalanced force is present.
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Answer:i dont remember
Explanation: ?>>> confused
