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Svetlanka [38]
3 years ago
12

If the force being applied to an object is doubled, what will happen to its acceleration?

Physics
1 answer:
Minchanka [31]3 years ago
4 0

Answer:

Acceleration decreases.

Explanation:

Hope this helps you.

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A child pushes a toy box across the floor in 5 seconds. If he did 30 J of work on the toy box, what amount of power was required
s2008m [1.1K]
My answer is 6 watts because 30J/5s is 6
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3 years ago
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An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane travel
Licemer1 [7]

Answer:

v=4.44\frac{m}{s}

Explanation:

Given that the airplane starts from the rest (this is initial velocity equals to zero)  and accelerates at a constant rate, position can be described like this: x=v_{0}t +\frac{1}{2} at^{2} where x is the position, t is the time a is the acceleration and v_{0} is initial velocity. In this way acceleration can be found. a=\frac{2(x-v_{0}t) }{t^{2} } =\frac{2(1.11m-0)}{1s^{2} } =2.22\frac{m}{s^{2} }.

Now we are able to found velocity at any time with the formula: v=v_{0} +at = 0\frac{m}{s} +(2.22\frac{m}{s^{2}}.2s)=4.44\frac{m}{s}

3 0
3 years ago
Un prisma de cemento pesa 2500 N y ejerce una presión de 125 Pa, ¿cuál es el valor del área en la cual se apoya?
Eduardwww [97]

Answer:

Area = 20 m²

Explanation:

Given the following data;

Force = 2500 N

Pressure = 125 Pa

To find the area on which it rest;

Mathematically, pressure is given by the formula;

Pressure = \frac {Force}{area}

Making area the subject of formula, we have;

Area = \frac {Force}{pressure}

Substituting into the formula, we have;

Area = \frac {2500}{125}

Area = 20 m²

3 0
3 years ago
One of the advantages of alternating current (ac) over direct current (dc) is the ease with which voltage levels can be increase
Svet_ta [14]

Answer:

True

Explanation:

In an alternating current, voltage levels can be easily increased or decreased as per the requirements of the energy distribution in practical world.

Hence, the given statement is true

3 0
3 years ago
If a 42kg rolling object slows from 11.5m/s to 3.33m/s how much work did friction do
geniusboy [140]

Answer: 1608.39 J

Explanation: Given that the

mass M = 42kg

U = 11.5m/s

V = 3.33m/s

how much work did friction do

Work done = Force × distance

Work done = Ma × distance

But acceleration a = V/t

Work done = M × V/t × d

Work done = M × V × d/t

Where d/t = velocity

Therefore,

Work done = M × U × V

Work done = 42 × 11.5 × 3.33

Work done = 1608.39 J

8 0
3 years ago
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