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gizmo_the_mogwai [7]
3 years ago
10

During the first 5 seconds of a rocket launch, the momentum of the rocket increased by 10,000 kg m/s. What was the impulse appli

ed to the rocket during this time?
Physics
1 answer:
Pavel [41]3 years ago
7 0

Answer:

10,000 kg m/s

Explanation:

The impulse exerted on an object is equal to the change in momentum of the object itself:

I=F \Delta t = \Delta p

where

I is the impulse

F is the force applied

\Delta t is the time during which the force has been applied

\Delta p is the change in momentum

In this problem, we are already given the change in momentum of the rocket: since the rocket starts from rest, its change in momentum is equal to its momentum after 5 seconds,

\Delta p = 10,000 kg m/s

and so, the impulse is equal to this value.


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