Answer:
When the bear eats salmon, the bear is functioning as a tertiary consumer (this is because salmon is a secondary consumer, since salmon eat herring that eat zooplankton that eat phytoplankton, that make their own energy from sunlight).
Explanation:
1st step: Transcription
DNA is unraveled and used as a template to form complimentary mRNA
mRNA then leaves nucleus in order to attach to ribosome and start 2nd step.
2nd step: Translation
tRNA with aminoacids attached will try to join mRNA\ribosome complex if tRNA triple codon matches the mRNA code it will attach aminoacid to start forming protein. This process continues until mRNA reaches STOP code, resulting in a long chain of aminoacids.
3rd step: Protein folding and modification
Usually performed by chaperonins and eventually golgi complex. Chaperonins assist in proper protein folding, while golgi apparatus performs final modifications.
Answer:
Photosynthesis is a process by which plants and photosynthetic bacteria obtain their food in presence of sunlight from water and carbon dioxide. They produce glucose as the food and oxygen is emitted as the byproduct. The equation for photosynthesis is - 6CO
2
+12H
2
O→C
6
H
12
O
6
+6H
2
O+6O
2
↑.
Thus, the correct answer is 'Photosynthesis.'
Explanation: hope this helps!
Mitosis is a part of the cell cycle when replicated chromonsomes are separated into two new nuclei.
Complete question:
Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the disease and blood group are independently inherited.
A normal man with type A blood and a normal woman with type B blood have already had one child with the disease. The woman is now pregnant for a second time.
Assuming that both parents are heterozygous for the gene that causes the disease, what is the probability that the second child will also have the disease? Express your answer as a fraction using the slash symbol and no spaces (for example, 1/2).
Answer:
The probability that the second child will also have the disease is 1/16.
Explanation:
<u>Available data:</u>
- Two genes independently inherited: one for blood type, the other for disease
- Man with type A blood x Woman with type B blood
- Both parents are heterozygous for the gene that causes the disease; Dd
If the man has A blood, and the woman has B blood, and they already have an affected child, this means that they must be heterozygous for blood type too.
Cross:
Parentals) AiDd x BiDd
Gametes) AD Ad iD id BD Bd iD id
Punnett square) AD Ad iD id
BD ABDD ABDd BiDD BiDd
Bd ABDd ABdd BiDd Bidd
iD AiDD AiDd iiDD iiDd
id AiDd Aidd iiDd iidd
F1) <u>Genotype</u>:
1/16 ABDD
2/16 ABDd
1/16 ABdd
1/16 AiDD
1/16 BiDD
2/16 AiDd
2/16 BiDd
1/16 Aidd
1/16 Bidd
1/16 iiDD
2/16 iiDd
1/16 iidd
<u>Phenotype:</u>
3/16 A/B normal
4/16 A normal
4/16 B normal
3/16 0 normal
1/16 0 affected by the disease.
