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Lunna [17]
3 years ago
14

Paul have a juice container that holds 5 gallons of Juice drinks 4 pints of juice everyday how many full 5-gallon containers of

juice will he drink in 30 daysq
Mathematics
1 answer:
Firlakuza [10]3 years ago
6 0
He will drink 6 5-gallon containers of juice in 30 days.
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Mrs.joshi bought a saree for Rs 1750.she sold it at a profit of 4%.what would be her profit or loss percent ?​
bekas [8.4K]

Answer: Rs 1820

Step-by-step explanation:

This is profit, thus is it a percentage increase of 4%. Thus, she sold the saree for 104% of what she bought it for, Rs 1750.  Thus, simply do 1.04*1750 to get 1820.

<em>Hope it helps <3</em>

7 0
3 years ago
You are at a stall at a fair where you have to throw a ball at a target. There are two versions of the game. In the first
Tomtit [17]

Answer:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Alternative 1

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=3, p=0.1)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We can find the probability of loss like this P(X=0) and if we find this probability we got this:

P(X=0)=(3C0)(0.1)^0 (1-0.1)^{3-0}=0.729

And the probability of loss with the first wersion is 0.729

Alternative 2

Let Y the random variable of interest, on this case we now that:

Y \sim Binom(n=5, p=0.05)

The probability mass function for the Binomial distribution is given as:

P(Y)=(nCy)(p)^y (1-p)^{n-y}

Where (nCx) means combinatory and it's given by this formula:

nCy=\frac{n!}{(n-y)! y!}

We can find the probability of loss like this P(Y=0) and if we find this probability we got this:

P(Y=0)=(5C0)(0.05)^0 (1-0.05)^{5-0}=0.774

And the probability of loss with the first wersion is 0.774

As we can see the best alternative is the first version since the probability of loss is lower than the probability of loss on version 2.

4 0
4 years ago
Which graph represents the function f(x)=4*3^x (f times x equals 4 times three to the power of x)
pychu [463]

Answer:

The answer to your question is the first graph in the second line.

Step-by-step explanation:

First graph in the first line: it shows a positive graph that intercepts the y-axis in 5, then this graph is not the correct answer.

Second graph in the first line: it shows a negative graph, this option is incorrect, we look for a positive graph.

First graph in the second line: is correct because is a positive graph and intercpts the y-axis in 4.

Second graph in the second line: is incorrect although it is a positive graph, it intercepts the y-axis in 3.

7 0
3 years ago
Find the average rate of change between f(-7) and f(-1) in the function f(x)=x^2+2x -8
Levart [38]

Answer:

- 6

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

here [ a, b ] = [ - 7, - 1 ]

f(b) = f(- 1) = (- 1)² + 2(- 1) - 8 = 1 - 2 - 8 = - 9

f(a) = f(- 7) = (- 7)² + 2(- 7) - 8 = 49 - 14 - 8 = 27

Hence

average rate of change = \frac{-9-27}{-1-(-7)} = \frac{-36}{6} = - 6

4 0
3 years ago
6. Find m<br><br> Btw if taking the test the first 5 answers are bbacd
erastovalidia [21]

Answer:


Step-by-step explanation:


7 0
3 years ago
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