Question:
1) The kick is good! The ball passes about 10 feet above the crossbar.
2) The kick is good! The ball clears the crossbar by approximately 14 feet.
3) The kick is good! The ball clears the crossbar by about 4 feet.
4) The kick is not successful. The ball is 2 feet too low.
Answer:
The correct option is;
3) The kick is good! The ball clears the crossbar by about 4 feet.
Step-by-step explanation:
Here we have
Horizontal distance from goal, x = 36 yards = 108 ft
Vertical distance of goal, y = 10 ft
Angle of elevation of ball = 34°
Initial velocity of ball, v₀ = 68 ft/s
∴ Vertical component of velocity = = v₀×sin(θ₀)×t - g×t
Horizontal component of velocity = vₓ = 68×cos(34) = 56.375 ft/s
The equation for projectile motion is as follows
x = x₀ + v₀×cos(θ₀)×t
y = y₀ + v₀×sin(θ₀)×t - 1/2×g×t²
Where:
x₀ = Initial horizontal displacement of the ball = 0
y₀ = Initial vertical displacement of the ball = 0
t = Time of flight of the ball
Therefore;
108 = 0 + 68×cos(34)×t which gives;
t = 108/56.375 = 1.916 seconds
Hence, y = y₀ + v₀×sin(θ₀)×t - 1/2×g×t² gives;
y = 0 + 68×sin(34)×1.916 - 1/2×32.2×1.916²
y = 72.85 - 59.09 = 13.76 ft, hence the vertical location of the ball at 36 yard is 13.76 ft where the crossbar is at 10 ft hence the ball clears the crossbar by 13.76 ft - 10 ft = 3.76 ft ≈ 4 ft
Therefore, the kick is good! The ball clears the crossbar by about 4 feet.
Answer:
1727 inches or approximately 143.91667 feet
Step-by-step explanation:
circumfrence is the so its
. this gives you a circumfrence of 69.08 inches which is eaual to one revolution. you simply have to do
inches. I didnt know if you also needed the answer in feet, so i divided that by 12 to get an approxamation of 143.91667 feet (it comes out with a repeating 6, so i rounded it to 7 on the third to six be accurate).
