When raising a fraction to a power, we can raise the numerator and denominator to the power. To find x, we need to find the cube root of both 125 and 27. That is, the numbers that when multiplied by themseelves 3 times result in 125 and 27.
![\sqrt[3]{125} = 5](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B125%7D%20%3D%205%20)
![\sqrt[3]{27} =3](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27%7D%20%3D3)
So x =
Answer:
The solution is (2,6)
Step-by-step explanation:
Let
x-----> the number of hours to change a fuel injection unit
y-----> the number of hours to change a transmission
we know that
5x+10y=70 -----> equation A
8x+8y=64 -----> equation B
Solve the system of equations by graphing
Remember that the solution of the system of equations is the intersection point both graphs
The solution is the point (2,6)
see the attached figure
Hello!
To find our answer, we just divide.
57/60=0.95
We multiply by 100 to find our percent
100(0.95)-95
Therefore, our answer is 95%
I hope this helps!
(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
