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Mars2501 [29]
3 years ago
14

1. Make sure to respond with complete sentences! Show all work please:)

Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0

Explanation:

The numerator of the rational exponent will be the product of the exponents inside and outside the radical: 5·7=35. The denominator of the rational exponent will be the index of the radical: 6. Then the equivalent expression is x^(35/6)

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2/3=1.2/x solve for x
Anvisha [2.4K]

First isolate x by multiplying by x on both sides.  It will look like this:

(2/3)x=1.2

Then devise by (2/3) on both sides to get:

x= 1.2/(2/3)

The easiest way to get this is plug that into a calculator and get the answer:

x=1.8

5 0
3 years ago
Which statement is true?
sweet-ann [11.9K]

Answer:

D

Step-by-step explanation:

so by process of elimination it can’t be A as it is a 7hr journey

B is also incorrect as she travels 50mph not an additional 50miles per hour (50m in hour one then 100m in hour 2 )

C is also incorrect as she travels 50 miles in ann hour not in 6

D is correct as she has travelled 200 miles


3 0
3 years ago
Help please very much
Norma-Jean [14]

Answer:

D

Step-by-step explanation:

3 0
2 years ago
Horizontal lines are always perpendicular to _________ lines.
Viktor [21]

Answer:

Vertical

Step-by-step explanation:

/_

6 0
3 years ago
A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
2 years ago
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