Hey there! I'm happy to help!
We want to find the probability that the player makes at least seven out of eight free throws. First, we find the probability of them making seven free throws.

Then, we find the probability of them making eight, which is another possibility that fits this.

Now, we add the probability of these two events happening.

Therefore, the probability that the player makes at least seven of eight free throws is 3/256 or about 1.17%
Have a wonderful day! :D
Answer:
2(7a + 4)
Step-by-step explanation:
2(7a + 4)
Answer:
6
Step-by-step explanation:
Answer: Children tickets cost 7.50
Adult tickets cost 12.50
Step-by-step explanation:
Let a represent adult tickets
Let c represent child tickets
On the first day she sells 6 adult tickets and 5 children tickets for total of 112.50. This can be written as:
6a + 5c = 112.50 ...... equation i
On the second day she sells 8 adult tickets and 4 children tickets for the total 130. This can be written as:
8a + 4c = 130 ....... equation ii
6a + 5c = 112.50 ...... equation i
8a + 4c = 130 ....... equation ii
Multiply equation i by 4
Multiply equation ii by 5
24a + 20c = 450 ........ equation iii
40a + 20c = 650 ......... equation iv
Subtract iii from iv
16a = 200
a = 200/16
a = 12.50
Adult tickets cost 12.50
From equation ii,
8a + 4c = 130
8(12.50) + 4c = 130
100 + 4c = 130
4c = 130 - 100
4c = 30
c = 30/4
c = 7.50
Children tickets cost 7.50
Answer:
I believe the correct answer is - The value of a bank account with quarterly compounded interest after 6 years.
I'm not sure if this is 100% correct but hope it helps.