All categories

3 years ago

What's 23/4 on a number line?

Mathematics

1 answer:

Eva8 [605]3 years ago

6 0

It should be 5.75 on a number line... I'm not sure what form you need that number in though

You might be interested in

A high speed train travels a distance of 503 km in 3 hours.

tensa zangetsu [6.8K]

The average speed, in km/minute, of the train is 2.79 km/minute

<h3>Calculating average speed </h3>

From the question, we are to calculate the average speed in km/minute

From the given information,

Distance travelled = 503 km

Time taken = 3 hours = 3 × 60 minutes = 180 minutes

Using the average speed formula,

Average speed = Distance / Time

∴ Average speed of the train = 503 / 180

Average speed of the train = 2.79 km/minute

Hence, the average speed, in km/minute, of the train is 2.79 km/minute

Learn more on Calculating average speed here: brainly.com/question/12025128

#SPJ1

3 0

1 year ago

35/9 simplified to it’s simplest form

MariettaO [177]

Answer:

$3\frac{8}{9}$

Step-by-step explanation:

5 0

3 years ago

Solve this equation 2(x+3)=x-4

horrorfan [7]

Answer: The answer is x = -10

5 0

2 years ago

Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?

bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function $f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}$

We need to determine the value of f(-6)

The value of f(-6) can be determined by substituting the value for $x=-6$ in the function and simplify the function.

Hence, let us substitute $x=-6$ in the function, we get,

$f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}$

Let us apply the rule $-\left(-a\right)=a$ , we get,

$f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}$

Multiplying the numbers, we get,

$f(-6)=\frac{100}{-10+e^{0.6}}$

The value of $e^{0.6}=1.822$

Substituting the value of $e^{0.6}=1.822$ , we get,

$f(-6)=\frac{100}{-10+1.822}$

Subtracting the denominator, we have,

$f(-6)=\frac{100}{-8.178}$

Dividing, we have,

$f(-6)=-12.228$

Rounding off to the nearest tenth, we have,

$f(-6)=-12.2$

Thus, the value of f(-6) is -12.2

4 0

2 years ago

Simplify. (x6 y3)(−8xy2)(−6x3)

meriva

When simplifying this, we would have to take this little by little in serious steps and not only this, but to also take notice of the use of <u>pemdas</u> and to make sure that we take each step carefully.

We first would <u></u><u>(first)</u> simplify the following:

$(((x^6)*(y^3))*(0-(8x*(y^2))))*(0-(2*3x^3)) \\ \\ then \ we \ would \ do . . . . \\ \\ x^7 \ multiplied \ by \ x^3 \ = x^(^7^ +^ 3^) = \ x^1^0 \\ \\ (last \ step).... \\ \\ 2^3 \ multiplied \ by \ 2^1 = 2^(^3^ +^ 1^) = 2^4 \\ \\ \Longrightarrow \ (your \ answer) \\ \\ \boxed{\bf{ (2^4*3x^1^0y^5)}}$

7 0

3 years ago