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jasenka [17]
4 years ago
9

X4y(4) = yx2(13), calculate (x+y)2

Mathematics
1 answer:
Delicious77 [7]4 years ago
3 0

Please, for clarity, use " ^ " to denote exponentiation:


Correct format: x^4*y*(4) = y*x^2*(13)

This is an educated guess regarding what you meant to share. Please err on the side of using more parentheses ( ) to show which math operations are to be done first.


Your (x+y)2, better written as (x+y)^2, equals x^2 + 2xy + y^2, when expanded.

The question here is whether you can find this x^2 + 2xy + y^2 in your

"X4y(4) = yx2(13)"


Please lend a hand here. If at all possible obtain an image of the original version of this problem and share it. That's the only way to ensure that your helpers won't have to guess what the problem actually looks like.


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What is the equation of a line that passes through the points (3, 6) and (8, 4) in slope intercept form?
MrMuchimi

Answer:

y=-\frac{2}{5}x +8.4

Step-by-step explanation:

Gradient

m =\frac{y-y1}{x-x1}

m = \frac{6-4}{3-8}

m=-\frac{2}{5}

Equation of a line

(y-y1)=m(x-x1)\\

- Sub one set of points into equation

(y-6)= -\frac{2}{5} (x-6)

y=-\frac{2}{5}x +8.4  

6 0
3 years ago
5 x 3 x 2 +3/0 -45/3+1 =
Norma-Jean [14]

5 \times 3 \times 2 +  \frac{3}{0}  -  \frac{45}{3}  + 1 =  \\  \\  =  \frac{3}{0} \\  \\ or \\  \\ 1. \: 30 +  \frac{3}{0}   -  \frac{45}{3}  + 1 \\ 2. \: 30 +  \infty  -  \frac{45}{3}  + 1 \\ 3. \: 30 +  \infty  - 15 + 1 \\ 4. \:  \infty

Yeah it's Impossible

4 0
3 years ago
Read 2 more answers
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
What is the volume of this cube help pl I need it fast
babunello [35]

Answer:

6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Answer this question please and thank you
Murljashka [212]

Answer:

1

1

0

0

Step-by-step explanation:

here´s and example for 1

1⁵

1x1x1x1x1=1

so 1 raised to the power of any number is 1

1 multiply by itself any number of times is 1

here´s an example for 0

0⁴

0x0x0x0=0

hence, the vale of 0 raised to any power is 0.

0 multiplied by itself any number of times is 0

8 0
3 years ago
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