Ask question

Ask question

All categories

3 years ago

11

Joanne has a rectangular kitchen that is 10 ft by 15 ft. She decides to increase the length and the width by the same amount (x)

in order to have a new kitchen whose area is double the area of the original kitchen. How much should the length and the width increased by?

1 answer:

Elodia [21]3 years ago

8 0

Answer:

NO

Step-by-step explanation:

You might be interested in

Please help with this.

icang [17]

Answer:

g(1)=-72; g(n)=g(n-1)*(1/6)

Step-by-step explanation:

g(1)= -72*(1/6)^(1-1)=-72*(1/6)^0=-72*1=-72

g(2)=-72*(1/6)^(2-1)=-72*(1/6)^1=-72*(1/6)=-12

g(2)=g(1)*(1/6)

g(n)=g(n-1)*(1/6)

5 0

2 years ago

Read 2 more answers

A random sampling of a company's monthly operating expenses for n=36 months produced a sample mean of $5474 and a stan-dard devi

lilavasa [31]

Answer with explanation:

Mean of the sample(m) = $ 5474

Standard deviation of the sample (S)=764

Number of observation(n)=36

$Z_{90 \text{Percent}}=Z_{0.09}=0.5359$

$z_{score}=\frac{\Bar x-\mu}{\frac{S}{\sqrt{n}}}\\\\0.5359=\frac{5474- \mu}{\frac{764}{\sqrt{36}}}\\\\0.5359=\frac{5474- \mu}{\frac{764}{6}}\\\\764 \times 0.5359=6 \times (5474- \mu)\\\\409.4276=32844-6 \mu\\\\6 \mu=32844 -409.4276\\\\ 6 \mu=32434.5724\\\\ \mu=\frac{32434.5724}{6}\\\\ \mu=5405.76$

So, Mean Monthly Expenses of Population =$ 5405.76, which is 90% upper confidence bound for the company's mean monthly expenses.

4 0

2 years ago

The diagram below shows a shaded parallelogram drawn inside a rectangle. Using Pythagoras, find the hypotenuse of triangle A and

Julli [10]

Answer: 5.9 cm for both triangles.

Step-by-step explanation:

Hi, since the situation forms 2 right triangles we have to apply the Pythagorean Theorem:

c^2 = a^2 + b^2

Where c is the hypotenuse of a triangle (the longest side of the triangle) and a and b are the other sides.

Replacing with the values given:

c^2 = 3^2 + 5^2

c^2 = 9+25

c^2 = 34

c = √34

c = 5.9 cm

Since both triangles are identical ( same side lengths) the hypotenuse is the same for both, 5.9 cm.

Feel free to ask for more if needed or if you did not understand something.

5 0

2 years ago

How can you use a point on the graph of f –1(x) = 9x to determine a point on the graph of f(x) = log9x?

Anastasy [175]

Whenever you can invert a function, you have that the graphs of $f(x)$ and its inverse $f^{-1}(x)$ are reflected with respect to the line $y=x$

So, given any point on the graph of $f^{-1}(x)$ , you can simply swap its coordinates to get the correspondent point on the original function $f(x)$

As an example, all exponential functions pass through the point $(0,1)$ , while all the logarithmic functions pass through the point $(1,0)$

6 0

3 years ago

Read 2 more answers

Can someone help with question 3

kirza4 [7]

Answer:

This is what you have to explain:

With 5n, you are multiplying a number and a variable.

With 5 + n, you are adding a number and a variable.

4 0

3 years ago