Answer:
Explanation:
#include <iostream>
using namespace std;
int costdays(int);
int costhrs(int,int);
int main()
{
int dd,hh,mm,tmph,tmpd,tmpm=0;
int pcost,mcost=0;
cout<<"Enter Parking time" << endl;
cout<<"Hours: ";
cin>>hh;
cout<<"Minutes: ";
cin>>mm;
if (mm>60)
{
tmph=mm/60;
hh+=tmph;
mm-=(tmph*60);
}
if (hh>24)
{
tmpd=hh/24;
dd+=tmpd;
hh-=(tmpd*24);
}
if ((hh>4)&&(mm>0))
{
pcost+=costdays(1);
}
else
{
mcost=costhrs(hh,mm);
}
cout<<"Total time: ";
if (dd>0)
{
cout<<dd<<"days ";
pcost+=costdays(dd);
}
pcost+=mcost;
cout<<hh<<"h "<<mm<<"mins"<<endl;
cout<<"Total Cost :"<<pcost<<"Won";
return 0;
}
int costdays(int dd)
{
return(dd*25000);
}
int costhrs(int hh,int mm)
{
int tmpm, tmp=0;
tmp=(hh*6)*1000;
tmp+=(mm/10)*1000;
tmpm=mm-((mm/10)*10);
if (tmpm>0)
{
tmp+=1000;
}
return(tmp);
}
To start combining, select the Merge Mode option on the Comparison tab. Next, click the button next to the line you wish to merge in order to replace content from the right pane with content from the left pane.
<h3>How is boundary layer thickness calculated?</h3>
- Where x is a position parallel to the wall, y is a coordinate normal to the wall, v is a (small) viscosity, u = (u, v) is the velocity, is the vorticity, and so on. The boundary conditions are as follows: u(x,y = +,t) = U, and u(x,y = 0,t) = 0.
- To gauge the overall pressure, a vertically sliding Pitot tube is employed. So that the growth of the boundary layer in the flow direction can be seen, the total pressures can be recorded at various distances from the plate surface. Static pressure is gauged at a different measurement location.
- To start combining, select the Merge Mode option on the Comparison tab. Next, click the button next to the line you wish to merge in order to replace content from the right pane with content from the left pane. Alternatively, you can pick a discrepancy and choose Replace Content from the Comparison tab.
To learn more about Boundary conditions refer to:
brainly.com/question/23802083
#SPJ4
44–66
According to sources, the most probable answer to this query is 44–66 point size.
This is because the eyes and the illustration should match the proportion of distance and height factors.
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Answer:
b) Bounded Waiting
Explanation:
int currentThread = 1;
bool thread1Access = true;
bool thread2Access = true;
thread1 { thread2 {
While (true) {
While (true)
{
while(thread2Access == true)
{
while(thread1Access == true)
{
If (currentThread == 2) {
If (currentThread == 1)
{
thread1Access = false; thread2Access = false;
While (currentThread == 2);
While (currentThread == 1);
thread1Access = true; thread2Access = true;
} }
/* start of critical section */ /* start of critical section */
currentThread = 2 currentThread = 1
… ...
/* end of critical section */ /* end of critical section */
thread1Access = false; thread2Access = false;
… ...
} }
} }
} }
It can be seen that in all the instances, both threads are programmed to share same resource at the same time, and hence this is the bounded waiting. For Mutual exclusion, two threads cannot share one resource at one time. They must share simultaneously. Also there should be no deadlock. For Progress each thread should have exclusive access to all the resources. Thus its definitely the not the Progress. And hence its Bounded waiting.
