When we are given a system of 3 linear equations, with 3 variables, we proceed as follows:
We consider 2 pairs or equations, for example (1, 2) and (2, 3), and eliminate one of the variables in each pair, creating a system of 2 linear equations with 2 unknowns.
Note that the third equation contains -2y which can be used to eliminate easily -6y in the second equation, and -4y in the fourth.
i) consider equations 1 and 3:
-3x-4y-3z=-7
5x-2y+5z=9
multiply the second equation by -2:
-3x-4y-3z=-7
-10x+4y-10z=-18
adding the 2 equations we have -13x-13z=-25
ii) consider equations 2 and 3. Multiply the third equation by -3:
2x-6y+2z=3
-15x+6y-15z=-27
adding the 2 equations we have -13x-13z=-24
So we got -13x-13z is -25, but also -24. this means the system is inconsistent, so it has no solution.
Answer: the system has no solutions
Answer:
1.) 357
2.) 221.5
3.) 72
4.) 1653
5.) 265
6.) 296
7.) 43.16
8.) 136
9.) 2486.33
10.)a. 48 b. 3
11.) 79
explantion: It breaks down a division problem into a series of easier steps. As in all division problems, one number, called the dividend, is divided by another, called the divisor, producing a result called the quotient.
https://www.theschoolrun.com/what-is-long-division
Step-by-step explanation:
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C = Wtc/1000
1000C = Wtc
Wtc = 1000C
W = (1000C) / (tc)
This is assuming that C and c are not the same.
If they are the same, we have:
W = (1000) / t, provided ,that C and c are not equal to 0.
Answer
-64
just use ur calculator since my teacher let us use the calculator i just typed in 16.(-4) and got -64
