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SOVA2 [1]
2 years ago
7

3)A ball is kicked from a height of 2 feet off the ground, after 1 second the ball rea

Mathematics
1 answer:
MArishka [77]2 years ago
3 0

Answer:

y = - 2x + (1/2 38) + 2   = y =  -2x + 19x + 2  at any second  and y = -2x^2 / 2  + 19/2 + 2/2 = <u>- x^2 + 19/2 + 2 </u>=  - x (4) + 19/2(4) + 1 = -4+ 38 + 1 = 35 seconds  

Step-by-step explanation:    We see that 38-2ft = 36ft and y intercept  = 2 and then -2x allows us to represent the starting point 2 as -2 (1) to allow a descend to our back to 0 for y  one we find y intercept we know - x^2  is our simplified equation and an input into this to find the static and slowed descend back to 0  if you keep inputting at 5 and 6 you see the equation speed up   Anyway at (4) substitute = 4 seconds we divide our simplified equation a = -x2 into  a b c and divide each by 2  before working out the<u> </u><u>decline</u> of the equation<u> (as equation still represents all ascending and descending) </u>for the 4th second as the height was <u>already said to be at its max at 38 feet see equation in answer to find 4 as substitute for x </u>

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