Answer:
10%
Step-by-step explanation:
Given: CP of lemon is $600.
3/4 of lemon sold at 20% loss
Remaining lemon at 20% gain.
Considering the quantity of lemon remain constant.
Cost price of 3/4 of lemon= 
As given, 3/4 of lemon sold at 20% loss.
∴ Selling price of 
Selling price= 
Hence, selling price of 3/4 lemon is $360.
Now, the cost price of remaining lemon 
∴ The cost price of
As given, remaining 
∴ Selling price of 
Selling price of 
Hence, selling price of 1/4 lemon is $180
Loss\profit percent= 
∴ Loss\profit percent= 
Hence, the loss percentage is 10%
Beaded braclets at 9 beads each
Then 156 beads = 156/9
17.333
But the answer is 17 braclets since she cannot make .333 of a braclet
Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z =
~ N(0,1)
where,
= population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P(
<
) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.
The reasoning would be that the pattern is going up by 3 every time. 13, 16
Answer:
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Step-by-step explanation: