One yard of ribbon cost 3 1/2 dollars how much would you pay for 5/8 of a yard? HELP PLEASE
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When two dice are rolled, then possible outcomes are
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Total possible outcomes = 36
In that, we count the ordered pairs that give us sum 5
(1,4) (2,3) (3,2) and (4,1) = 4 outcomes
Probability = (number of times the event occurs)/ (total number of outcomes)
P( sum of 5) = =