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- First find the area of the whole circle
The equation is :
πr^2
Substitute the radius in:
π(5)^2
Solve:
Area of full circle = 25π
(Note : leave this answer in terms of 'pi' so it is easier to handle
Next, find the area of the sector
The equation for this is:
(angle/360) x πr^2
Substitute the values in:
(80/360) x π(5)^2
Solve :
Area of sector = (50/9)π
Now, find the area of the triangle:
1/2 absinC
Substitute the values in:
1/2(5)(5) x sin(80) = 12.31009691
Subtract this answer from the area of the sector
Answer = 5.14319607
Subtract this from the area of the whole circle
Answer = 73.39662073
To the nearest tenth, that would be 73.4 cm^2
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Answer:
true
Step-by-step explanation:
The only regular (all sides equal and all angles equal) quadrilateral is a square. So all other quadrilaterals are irregular.
Answer:
7m(3m^6 - m^4 + 7)
Step-by-step explanation:
This is a factorization question
All we want to do here is to factor out 7m from each term of the polynomial
This becomes;
21m^7 -7m^5 + 49m = 7m (3m^6 - m^4 + 7)
