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Sergeeva-Olga [200]
3 years ago
14

You have 15 milliliters of a drink that contains 15% milk. How many millimeters of a drink containing 63% milk needs to be added

in order to have a final drink that is 45% milk?
Mathematics
1 answer:
Igoryamba3 years ago
8 0

Answer:

4 ml of the 63% milk drink

Step-by-step explanation:

Multiplying 15 ml by 0.15 results in 2.25 ml, the amount of whole milk in the drink.  Let m represent the number of ml of a drink that is 63% milk.

The final amount of milk drink that is to be 45% milk will be 15 ml + m, and the amount of whole milk contained in this drink will be 0.45(15 + m).

Then:

0.15(15 ml) + 0.63(m) = 0.45(15 + m), where m is to be in milliliters.

2.25 + 0.63m = 6.75 + 0.45m

First:  consolidate the m terms on the left.  0.63m less 0.45m yields 18 m; then we have:

2.25 + 18m = 6.75, or

18 m = 4.50, or m = 4 ml.

In conclusion:  adding 4 ml of that 63% milk drink to the initial 15 ml of 15% milk will result in (15 ml + 4 ml) of a 45% milk drink.            

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aliya0001 [1]

Answer:

40 ft squared

Step-by-step explanation:

To calculate area of a rectangle, you use the formula length times width, or base times height.

5 x 8 = 40 feet squared

5 0
3 years ago
In ΔPQR, the measure of ∠R=90°, the measure of ∠Q=38°, and RP = 72 feet. Find the length of PQ to the nearest tenth of a foot.
ASHA 777 [7]

Answer:

116.9 ft

Step-by-step explanation:

6 0
3 years ago
From the set {1, 3, 5}, use substitution to determine which value of x makes the equation true.
mixer [17]
{1,3,5}
ie, sub 1, 3 and 5 for x and see which one is true

20-2(1)=10
20-2=10
18=10
false

20-2(3)=10
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14=10
false

20-2(5)=10
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answer is 5
5 0
3 years ago
In his free time Gary spends 14 hours per week on the Internet and 10 hours per week playing video games. If Gary has five hours
Vikki [24]

Answer:

A

Step-by-step explanation:

If you add 14 and 10 you get 24.

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to find the percentage you just do 24/34=68.5%

5 0
3 years ago
Read 2 more answers
the weight of an object on mars varies directly as the weight of the object on earth a 90 pound object on earth weighs 34 pounds
Mariulka [41]

We have been given that the weight of an object on the mars varies directly as the weight of the object on earth.  

Let y be weight of an object on Mars and x be weight of an object on Earth.

\\
y=kx

We have been given that the weight of an object on Mars is 34 pounds and weight of the same object on Earth is 90 pounds.

Putting the given values in equation we get

\\
34=k(90)\\
\\
k=\frac{34}{90}=\frac{17}{45}

Therefore, our equation now becomes

\\
y= \frac{17}{45}x

Now we have been given that the weight of an object on Earth is 135 pounds and we have to find the weight of the same object on Mars,

We have been given that \\
x=135

Putting the given values in our equation we get

\\
y= \frac{17}{45}(135)=\frac{17\cdot 135}{45}=17\cdot 3 = 51

Therefore weight of the object on Mars will be 51 pounds.

                                                                             

7 0
4 years ago
Read 2 more answers
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