P,Q,R can't be 0, because their product is nonzero. Either of S and T could be 0, but the third one only works if S is 0.
<span>In this problem, to find the answer we have to setup a series of ratios that relate the scale to real life distance. We know that 1cm = 2.50km, so that ratio would be 1cm/2.5km. For two towns that are 4.75cm apart on the map, we set a ration of 4.75cm/x km, where x is the actual distance. Now we set the ratios equal to each other and solve for x. 1/2.5=4.75/x where x = 4.75*2.5/1 = 11.875 and rounding up we get 11.88 km. The two towns are actually 11.88 km apart from each other.</span>
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Answer:
x ≠ 3
Step-by-step explanation:
In any case, the domain is restricted to values of the variable for which the function is defined. The value 1/0 is not defined, so the variable cannot allow the denominator to be zero. The denominator x-3 will be zero for x=3, so that value of the variable cannot be in the domain.
The domain is all real numbers except x=3.
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<em>Additional comments</em>
It is useful to become familiar with the domains of different functions. As we saw above, the reciprocal of 0 is undefined. The square root of a negative number is undefined. The log of a non-positive number is undefined. Trig functions are defined everywhere, but their inverse functions are not. Polynomial functions are defined everywhere, but ratios of polynomials have the same restriction on denominators that we see above.
Answer:
Hence he will be 4 large containers and 4 small containers
Step-by-step explanation:
Given data
Let the number of small containers be x
and the number of large containers be y
x+y= 8---------1
also
2x+4y= 24-----2
the system of equation to solve the problem is
x+y= 8
2x+4y= 24
from 1
x=8-y
put this in 2
2(8-y)+4y= 24
16-2y+4y= 24
2y= 24-16
2y= 8
y= 8/2
y= 4
put y= 4 in 1
x+4=8
x= 8-4
x= 4
Hence he will be 4 large containers and 4 small containers
