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inessss [21]
3 years ago
5

Write this number in expanded form 719,927

Mathematics
2 answers:
iragen [17]3 years ago
8 0
700,000+10,000+9,000+900+20+7
mixer [17]3 years ago
6 0
Seven hundred and nine-teen thousand, nine hundred and twenty seven
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Why is school so boring
Elanso [62]

Answer:

because life sucks

Step-by-step explanation:

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Perry surveyed 60 students at her school and found that 0.45 of the students she surveyed said their favorite class is math. Ano
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the answer is 27 students
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Find sin(2x), cos(2x), and tan(2x) from the given information.<br> tan(x) = − 1/2 , cos(x) &gt; 0
vodomira [7]

Answer:

  • sin(2x) = -4/5
  • cos(2x) = 3/5
  • tan(2x) = -4/3

Step-by-step explanation:

It may be easiest to start with tan(2x).

  tan(2x) = 2tan(x)/(1 -tan(x)²)

  tan(2x) = 2(-1/2)/(1 -(-1/2)²) = -1/(3/4)

  tan(2x) = -4/3 . . . . . still a 4th-quadrant angle

__

Then cosine can be found from ...

  cos(2x) = 1/√(tan(2x)² +1) = 1/√((-4/3)²+1) = √(9/25)

  cos(2x) = 3/5

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Sine can be found from these two:

  sin(2x) = cos(2x)tan(2x) = (3/5)(-4/3)

  sin(2x) = -4/5

5 0
3 years ago
25 kids took a math test. If 20 kids passed the test, what percent of kids did not pass the test?
nata0808 [166]

Answer: 20%

Step-by-step explanation:

25 = 100%

25/5 = 5

100/5 = 20

That means 80% passed and 20% didnt.

4 0
3 years ago
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Find all real zeros of 4x^3-20x+16
Pani-rosa [81]

Answer:

  {1, (-1±√17)/2}

Step-by-step explanation:

There are formulas for the real and/or complex roots of a cubic, but they are so complicated that they are rarely used. Instead, various other strategies are employed. My favorite is the simplest--let a graphing calculator show you the zeros.

___

Descartes observed that the sign changes in the coefficients can tell you the number of real roots. This expression has two sign changes (+-+), so has 0 or 2 positive real roots. If the odd-degree terms have their signs changed, there is only one sign change (-++), so one negative real root.

It can also be informative to add the coefficients in both cases--as is, and with the odd-degree term signs changed. Here, the sum is zero in the first case, so we know immediately that x=1 is a zero of the expression. That is sufficient to help us reduce the problem to finding the zeros of the remaining quadratic factor.

__

Using synthetic division (or polynomial long division) to factor out x-1 (after removing the common factor of 4), we find the remaining quadratic factor to be x²+x-4.

The zeros of this quadratic factor can be found using the quadratic formula:

  a=1, b=1, c=-4

  x = (-b±√(b²-4ac))/(2a) = (-1±√1+16)/2

  x = (-1 ±√17)2

The zeros are 1 and (-1±√17)/2.

_____

The graph shows the zeros of the expression. It also shows the quadratic after dividing out the factor (x-1). The vertex of that quadratic can be used to find the remaining solutions exactly: -0.5 ± √4.25.

__

The given expression factors as ...

  4(x -1)(x² +x -4)

5 0
3 years ago
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