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ryzh [129]
3 years ago
14

The measure of an angle is 89 times the measure of its supplementary angle. What is the measure of each angle

Mathematics
1 answer:
Olegator [25]3 years ago
7 0

Answer:

2 and 178

Step-by-step explanation:

If we take an instance of a number 'x', according to the question we find that x+x*89=180(Because they are complementary)

We get, = 89x+x=180

=> 90x=180

=> x=180/90

=> x =2

So, we found that x=2 , hence the other angle is going to be 2*89=178

This is correct as 2+178=180(as they are supplementary to each other)

Hope this answer helps, Please mark me as brainliest, Thank you!

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How do you solve the system 3x-y z=5, x 3y 3z=-6, and x 4y-2x=12?
dlinn [17]
3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)

From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . .  (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)

(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5

From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3

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8 0
3 years ago
van someone please help me with this i dont need an explaination i just need a. b. c. or d. please and thank you
Talja [164]

Answer:

option C

f(x)=-\sqrt{x+3}+8

Step-by-step explanation:

we have

f(x)=-2\sqrt{x-3}+8

using a graphing tool

see the attached figure N1

The range is the interval--------> (-∞,8]

y\leq 8

case A) f(x)=\sqrt{x-3}-8

using a graphing tool

The range is the interval--------> [-8,∞)

y\geq -8

case B) f(x)=\sqrt{x-3}+8

using a graphing tool

The range is the interval--------> [8,∞)

y\geq 8

case C) f(x)=-\sqrt{x+3}+8

using a graphing tool

The range is the interval--------> (-∞,8]

y\leq 8

case D) f(x)=-\sqrt{x-3}-8

using a graphing tool

The range is the interval--------> (-∞,-8]

y\leq -8

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Answer:well I will tell if you tell me the answer for my question

Step-by-step explanation:

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Step-by-step explanation:

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