2x + 5 - 6x + 21 = 2(3x - 5) - 4
distribute
2x+5 -6x +21 = 6x-10 -4
combine like terms
-4x +26 = 6x -14
add 4x to each side
26 = 10x -14
add 14 to each side
40 = 10x
divide by 10
4 =x
D x=5 jhhhhhhgfrcrcrvtvrvtvrvgniby
This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
Any locker with a number that is a multiple of 8, 12, and 75 will contain all three animals.
The least common multiple of these three numbers is

and so any multiples of 600 between 1 and 3500 will contain all three animals. These are 600, 1200, 1800, 2400, and 3000.
Why is the LCM 600? You can determine that using the prime factorizations of the three given numbers:



The LCM can be obtained by multiplying as many prime numbers together as are needed to contain the prime factorizations of the three numbers. This is obtained with

(at least three 2s to get the 8; at least one 3 and two of the previous 2s to get 12; and at least two 5s along with the previous 3 to get 75)
Answer:
3x>12 2x/3 ≤ 6
3x>12, x = 4 2x/3, x = 2 ≤ 6