Let's solve this problem step-by-step.
STEP-BY-STEP SOLUTION:
We will be using simultaneous equations to solve this problem.
Let's establish the two equations we will be using to solve the problem.
Let Andrew's current age = a
Let Andrew's son's current age = s
Equation No. 1 -
a = 3s
Equation No. 2 -
a - 10 = 5s
To begin with, we will substitute the value of ( a ) from the first equation into the second equation to solve for ( s ).
Equation No. 2 -
a - 10 = 5s
( 3s ) - 10 = 5s
3s - 5s = 10
- 2s = 10
s = 10 / - 2
s = - 5
Next we will substitute the value of ( s ) from the second equation into the first equation to solve for ( a ).
Equation No. 1 -
a = 3s
a = 3 ( - 5 )
a = - 15
FINAL ANSWER:
Therefore, the present age of Andrew is - 15 and the present age of Andrew's son's is - 5.
It isn't possible for someone to be negative years old, but this is the answer that I ibtained from the equations.
Hope this helps! :)
Have a lovely day! <3
It would answer the same thing because as an example, 1+2=2+1 that would equal the same thing on both sides of the equation
Answer:
4) x = - 12
5) x = 4
Step-by-step explanation:
4)
Since points T and S are mid points of sides ML and MN of triangle MLN.
Therefore, by mid point theorem,
TS is half of LN
so,
5) In the same way x = 4 will be the correct answer in question number 5.
Answer:
or 10.29563
Step-by-step explanation:
Use the distance formula to determine the distance between the two points.
d = distance
= coordinates of the first point
= coordinates of the second point
Compare 1/7 to consecutive multiples of 1/9. This is easily done by converting the fractions to a common denominator of LCM(7, 9) = 63:
1/9 = 7/63
2/9 = 14/63
while
1/7 = 9/63
Then 1/7 falls between 1/9 and 2/9, so 1/7 = 1/9 plus some remainder. In particular,
1/7 = 1/9¹ + 2/63.
We do the same sort of comparison with the remainder 2/63 and multiples of 1/9² = 1/81. We have LCM(63, 9²) = 567, and
1/9² = 7/567
2/9² = 14/567
3/9² = 21/567
while
2/63 = 18/567
Then
2/63 = 2/9² + 4/567
so
1/7 = 1/9¹ + 2/9² + 4/567
Compare 4/567 with multiples of 1/9³ = 1/729. LCM(567, 9³) = 5103, and
1/9³ = 7/5103
2/9³ = 14/5103
3/9³ = 21/5103
4/9³ = 28/5103
5/9³ = 35/5103
6/9³ = 42/5103
while
4/567 = 36/5103
so that
4/567 = 5/9³ + 1/5103
and so
1/7 = 1/9¹ + 2/9² + 5/9³ + 1/5103
Next, LCM(5103, 9⁴) = 45927, and
1/9⁴ = 7/45927
2/9⁴ = 14/45927
while
1/5103 = 9/45927
Then
1/5103 = 1/9⁴ + 2/45927
so
1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/45927
One last time: LCM(45927, 9⁵) = 413343, and
1/9⁵ = 7/413343
2/9⁵ = 14/413343
3/9⁵ = 21/413343
while
2/45927 = 18/413343
Then
2/45927 = 2/9⁵ + remainder
so
1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/9⁵ + remainder
Then the base 9 expansion of 1/7 is
0.12512..._9