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kotykmax [81]
2 years ago
5

Find the savings plan balance after 18 months with an APR of 3% and monthly payments of $200.

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
4 0

The saving plan balance is $3,677.53.

Given that,

  • The no of months is 18.
  • The annual percentage rate is 3% so the monthly rate percentage is 0.25%.
  • And, the monthly payment is $200.

Based on the above information, the following formula should be used:

FVA = PMT×  [(1+r)^n - 1] ÷ r

= $200 × [(1+ 0.0025)^18 - 1] ÷ 0.0025

= $3,677.53

Therefore we can conclude that the saving plan balance is $3,677.53.

Learn more: brainly.com/question/14191332

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Which polynomial is represented by the algebra tiles? 2x2 – 4x – 6 2x2 4x 6 –2x2 – 4x – 6 –2x2 4x 6.
natta225 [31]

Polynomials consist of both indeterminates and coefficients. The polynomial that is been represented by the algebra tiles is 2x²-4x -6.

<h3>What are polynomials?</h3>

A polynomial consists of both indeterminates and coefficients and involves mathematical operations such as addition, subtraction, multiplication, and division.

In order to find the polynomial that is been represented by the tiles, we will simply, calculate the number of tiles for each variable,

As we can see in the image,

Number of tiles labeled as x² = 2

Number of tiles labeled as -x = 4

Number of tiles labeled '-' = 6

therefore, the polynomial can be written as 2x²-4x -6.

Hence, the polynomial that is been represented by the algebra tiles is 2x²-4x -6.

Learn more about Polynomials:

brainly.com/question/17822016

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2 years ago
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7 0
3 years ago
‼️10 point‼️URGENT‼️
Elena-2011 [213]

D. y=-3/10x+1/2

Step-by-step explanation:

Using rise/run you can count the units the line moves from one point to another, from the left point to the right point the line travels down 3 and over 10 so you get -3 as your rise (it is negative because the line is traveling downwards) and 10 as your run, so your slop is -3/10. By looking at the graph you can see that your y-intercept is 1/2. SO when plugged into y=mx+b with m as -3/10 and b as 1/2 you get the equation y=-3/10x+1/2, or letter D.

4 0
3 years ago
Solve for x. (X+10)(x+10)=0
atroni [7]

Answer:

use foil method-first inside outside last

Step-by-step explanation:

7 0
3 years ago
Read 3 more answers
State the number of possible triangles that can be formed using the given measurements.
romanna [79]

Answer:  39) 1              40) 2

                41) 1              42) 0

<u>Step-by-step explanation:</u>

39)     ∠A = ?        ∠B = ?       ∠C = 129°

            a = ?          b = 15         c = 45

Use Law of Sines to find ∠B:

\dfrac{\sin B}{b}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin B}{15}=\dfrac{\sin 129}{45}\rightarrow \quad \angle B=15^o\quad or \quad \angle B=165^o

If ∠B = 15°, then ∠A = 180° - (15° + 129°) = 36°

If ∠B = 165°, then ∠A = 180° - (165° + 129°) = -114°

Since ∠A cannot be negative then ∠B ≠ 165°

∠A = 36°        ∠B = 15°       ∠C = 129°       is the only valid solution.

40)      ∠A = 16°        ∠B = ?       ∠C = ?

             a = 15           b = ?         c = 19

Use Law of Sines to find ∠C:

\dfrac{\sin A}{a}=\dfrac{\sin C}{c} \rightarrow\quad \dfrac{\sin 16}{15}=\dfrac{\sin C}{19}\rightarrow \quad \angle C=20^o\quad or \quad \angle C=160^o

If ∠C = 20°, then ∠B = 180° - (16° + 20°) = 144°

If ∠C = 160°, then ∠B = 180° - (16° + 160°) = 4°

Both result with ∠B as a positive number so both are valid solutions.

Solution 1:  ∠A = 16°        ∠B = 144°       ∠C = 20°    

Solution 2:  ∠A = 16°        ∠B = 4°       ∠C = 160°    

41)       ∠A = ?        ∠B = 75°       ∠C = ?

             a = 7           b = 30         c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{7}=\dfrac{\sin 75}{30}\rightarrow \quad \angle A=13^o\quad or \quad \angle A=167^o

If ∠A = 13°, then ∠C = 180° - (13° + 75°) = 92°

If ∠A = 167°, then ∠C = 180° - (167° + 75°) = -62°

Since ∠C cannot be negative then ∠A ≠ 167°

∠A = 13°        ∠B = 75°       ∠C = 92°       is the only valid solution.

42)      ∠A = ?         ∠B = 119°       ∠C = ?

             a = 34         b = 34           c = ?

Use Law of Sines to find ∠A:

\dfrac{\sin A}{a}=\dfrac{\sin B}{b} \rightarrow\quad \dfrac{\sin A}{34}=\dfrac{\sin 119}{34}\rightarrow \quad \angle A=61^o\quad or \quad \angle A=119^o

If ∠A = 61°, then ∠C = 180° - (61° + 119°) = 0°

If ∠A = 119°, then ∠C = 180° - (119° + 119°) = -58°

Since ∠C cannot be zero or negative then ∠A ≠ 61° and ∠A ≠ 119°

There are no valid solutions.

6 0
3 years ago
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