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SOVA2 [1]
3 years ago
15

How do you solve 6(2/3x-3)>3

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0

Answer:

14>3

Step-by-step explanation:

you would need to turn the 3 in the parenthesis into a fraction which would result in 9/3. 2/3 - 9/3= -7/3      

Multiply the 7/3 by 6 and by what I have always been taught, you only multiply the top of the fraction. This would leave it to be 42/3 which would be known as 14.

So therefore the answer would be 14>3

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\bf \textit{area of a circle}\\\\&#10;A=\pi r^2~~&#10;\begin{cases}&#10;r=radius\\&#10;-----\\&#10;A=201.06&#10;\end{cases}\implies 201.06=\pi r^2&#10;\\\\\\&#10;\cfrac{201.06}{\pi }=r^2\implies \sqrt{\cfrac{201.06}{\pi }}=r\\\\&#10;-------------------------------

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Read 2 more answers
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