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3 years ago

How do you solve 6(2/3x-3)>3

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

4 0

Answer:

14>3

Step-by-step explanation:

you would need to turn the 3 in the parenthesis into a fraction which would result in 9/3. 2/3 - 9/3= -7/3

Multiply the 7/3 by 6 and by what I have always been taught, you only multiply the top of the fraction. This would leave it to be 42/3 which would be known as 14.

So therefore the answer would be 14>3

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88.27 rounded to the nearest one

Paladinen [302]

Answer:

[See Below]

Step-by-step explanation:

_______________________________

✦ Round $88.27$ to the nearest whole number:

$88$

✦ Round $88.27$ to the nearest Tenth:

$88.3$

_______________________________

~Hope this helps Mate. If you need anything feel free to message me.

$-Your~ Friendly~ Answerer,~ Shane$ ☺

6 0

3 years ago

Please help, will give brianlist. 1. Solve the equation. Show all of your work.

siniylev [52]

$x + \frac{3}{7 } = \frac{5}{7}$

$\frac{7x + 3}{7} = \frac{5}{7}$

$(7x + 3) \times 7 = 5 \times 7$

by cross multiplication.

$49x + 21 = 35$

$49x = 35 - 21$

$49x = 14$

$x = \frac{14}{49}$

$x = \frac{2}{7}$

3 0

3 years ago

Read 2 more answers

Integration of (3X(X^2+3)^4) dx <img src="https://tex.z-dn.net/?f=%20" id="TexFormula1" title=" " alt=" " align="absmiddle" c

dimaraw [331]

Answer:

Step-by-step explanation:

$\int 3x(x^2+3)^4 \ dx$ .

It is apparently obvious we could expand the bracket and integrate term-by-term. This method would work but is very time consuming (and you could easily make a mistake) so we use a different method: integration by substitution.

Integration by substitution involves swapping the variable $x$ for another variable which depends on x: $u(x)$ . (We are going to choose $u$ for this question).

The very first step is to choose a suitable substitution. That is, an equation $u=f(x)$ which is going to make the integration easier. There is a trick for spotting this however: if an integral contains both a term and it's derivative then use the substitution $u=\text{The Term}$ .

Your integral contains the term $x^2 + 3$ . The derivative is $2x$ and (ignoring the constants) we see $x$ is also in the integral and so the substitution $u=x^2+3$ will unravel this integral!

Step 2: We must now swap the variable of integration from x to u. That means interchanging all the x's in the integrand (the term being integrated) for u's and also swapping (dx" to "du").

$u=x^2+3 \Rightarrow \frac{du}{dx}=2x \Rightarrow dx = \frac{1}{2x} du$

Then,

$\int 3x(x^2+3)^4 \ dx = \int 3x \cdot u^4 \cdot \frac{1}{2x} du = \int \frac{3}{2}u^4\ du$ .

The substitution has made this integral is easy to solve!

$\int \frac{3}{2}u^4\ du= \frac{3}{10}u^5 + C$

Finally we can substitute back to get the answer in terms of x:

$\int 3x(x^2+3)^4 \ dx = \frac{3}{10}(x^2+3)^5+C$

8 0

3 years ago

A survey was taken on pet ownership. 750 people were covered on the first day of the survey. The number tripled every subsequent

wlad13 [49]

Day one: 750 * 1 = 750
day two: 750 * 3 = 2250
day three: 2250 * 3 = 6750
day four: 6750 * 3 = 20250
day five: 20250 * 3 = 60750
day six: 60750 * 3 = 182250
add it all together: 750 + 2250 + 6750 + 20250 + 60750 + 182250 = 273000

The answer is C, 273000.

6 0

4 years ago

Rosie bought a puppy. She weighed it for 2 months. The first month it weighed 2 1/2 pounds. Then she weighed it again the next m

Dvinal [7]

The puppy weights 3.75 pounds now

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3 years ago