Answer:
db / dt = kb
this becomes b(t) = Ce^(kt)
C = 100, the initial population
P(1) = 420 = 100 e^(1k)
4.2 = e^k
ln 4.2 = k
a) thus, b(t) = 100 e^(t ln 4.2)
b) b(3) = 100 e^(3 ln 4.2)
c) growth constant will still be ln 4.2 (constant percentage of populatioin)
d) 10000 = 100 e^(t ln 4.2)
100 = e^(t ln 4.2)
ln 100 = t ln 4.2
t = ln 100 / ln 4.2
Step-by-step explanation:
Yes because you automatically get 14 dollars and you could wide 84 dollars
Answer:
0.014767
Step-by-step explanation:
Are you trying to solve for c? if so c=8
Most of these problems are the commutative property:
Addition
a + b = b + a
Multiplication
a * b = b * a
and the associative property:
Addition
(a + b) + c = a + (b + c)
Multiplication
(a * b) * c = a * (b * c)
There's also the Identity property:
Addition \ Subtraction:
a + 0 = a \ a - 0 = a
Multiplication \ Division:
a * 1 = a \ a / 1 = a
