There are 8 circles and 6 squares. what is the simplest ratio of squares to 2 is divided by the difference of a number and 3.

F h(x) = 6 – x, what is the value of (h circle h) (10)?

insens350 [35]

Answer:

Step-by-step explanation: when h(x) = 10

h(x)= 6-x

h(10)= 6-10

=-4

6 0

2 years ago

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Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

Juan put three square tiles with sides 8 centimeters, 10 centimeters, and x centimeters together so that they form a right trian

Elan Coil [88]

Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to $x^{2}$ .
$A = x^{2}$ ---> equation (1)
By using pythagoras rule which states that the $x^{2} = hyp^2 - opposite^2$ ---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
$x^{2} = 10^{2} - 8^{2}$ substitute this value in equation (1) then
$A = x^{2} = 10^{2} -8^{2}$
where A is the area of the square whose side is x

6 0

2 years ago

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Worth 33 points each!!

gogolik [260]

Where x is the number of books sold, i is income, and c is cost:

c = 4x + 3500 ($4 per book plus the 3500 flat marketing fee)

i = 15x ($15 per book)

You are looking for the point where these intersect: the intersection is where the income is equal to the cost, and at any point after that the income is greater than the cost. So, set the equations equal to each other:

4x + 3500 = 15x

subtract 4x from both sides

3500 = 11x

divide both sides by 11

x = 318.181818

So, you would have to sell a minimum of 319 books in order to make a profit.

3 0

3 years ago

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The Product of a number m and 23

damaskus [11]

Answer:

23m

Step-by-step explanation:

The product of a number m and the numeral 23 is 23m.

6 0

3 years ago