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3 years ago

H(a)=2a-5 g(a)=a^2 Find h(g(a))

Mathematics

1 answer:

Arisa [49]3 years ago

6 0

H(g(a)) just basically means you’re plugging g(a) into a for h(a).
the answer would be 2(a^2)-5

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Softa [21]

Answer:

There are no true solutions to the equation.

Step-by-step explanation:

The correct equation is

$y+1=\sqrt{-2y-3}$

Solve for y

squared both sides

$(y+1)^2=(-2y-3)$

$(y^2+2y+1)=(-2y-3)$

$y^2+2y+1+2y+3=0$

$y^2+4y+4=0$

$(y+2)(y+2)=0$

$y=-2$

Verify

substitute the value of y in the original expression

$-2+1=\sqrt{-2(-2)-3}$

$-1=1$ ----> is not true

therefore

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serg [7]

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Answer:

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valentinak56 [21]

Answer:

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