4x-3 is the answer. Hope this helps:)
(e) it is the last one........
Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
-15 2/3.
Step-by-step explanation: First off, I performed the equation -4 5/1 - 6 4/6, yielding -15.6. I then translated that to a fraction. How to do that, you ask?
Example #1
Convert 0.32 to fraction:
0.32 = 32/100
Find the greatest common divisor (gcd) of the numerator and the denominator:
gcd(32,100) = 4
Reduce the fraction by dividing the numerator and the denominator with the gcd:
0.32 = (32/4) / (100/4) = 8/25
Example #2
Convert 2.56 to fraction:
2.56 = 2+56/100
Find the greatest common divisor (gcd) of the numerator and the denominator:
gcd(56,100) = 4
Reduce the fraction by dividing the numerator and the denominator with the gcd:
2+56/100 = 2 + (56/4) / (100/4) = 2+14/25
In your problem the final answer would result in -15 2/3. Hope this answered your question.
Answer:
5, 6
Step-by-step explanation:
When Kelvin rolls the dice twice, he can't get more than a 4 because if he did, the sum of the two numbers would be more than a 8. So, the numbers that cannot be the second number is 5 and 6.
