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Sati [7]
3 years ago
8

If it is 5 degrees outside and the temperature will drop 17 degrees in the next 6 hours how cold will it get?

Mathematics
2 answers:
ser-zykov [4K]3 years ago
7 0
5 - 17 = 12 so the answer is that it will be -12 degrees outside. Fahrenheit or Celsius??

Hope This Helps!
xeze [42]3 years ago
3 0
<span>if you take 5 and subtract 17 it will + -12 so then you know in the next 6 hour it will be -12</span>
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PLS HELP ILL GIVE BRAINLIEST!
lesantik [10]

Answer:

B

Step-by-step explanation:

-the base angles are 34, so the total value of both base angles is 68

-an isosceles triangle is equal to 180

-subtract 68 from 180 for the answer, so the equation is 68+x=180

hope this helps, comment in you have a question :)

8 0
3 years ago
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7)Twice a number when decreased by 7 gives 45. Find the number.​
kirza4 [7]
Isn’t it 26... cuz 26x2 is 52 then subtract 7 which is 45
4 0
3 years ago
How would you solve 4(y – 3y) – 19 = 32
Fittoniya [83]

Answer:

<u>y = - 6.375</u>

Step-by-step explanation:

Step 1:

4 ( y - 3y ) - 19 = 32        Equation

Step 2:

4y - 12y - 19 = 32         Multiply

Step 3:

- 8y - 19 = 32         Combine Like Terms

Step 4:

- 8y = 51        Add 19 on both sides

Step 5:

y = 51 ÷ - 8         Divide

Answer:

<u>y = - 6.375</u>

Hope This Helps :)

6 0
3 years ago
Please help me out with this please
ki77a [65]

Answer:

P = 9 is the max value

Step-by-step explanation:

Sketch

2x + 4y = 10

with x- intercept = (5, 0) and y- intercept (0, 2.5)

x + 9y = 12

with x- intercept = (12, 0) and y- intercept = (0, \frac{4}{3} )

Solve

2x + 4y = 10 and x + 9y = 12 to find the point of intersection at (3, 1)

The region corresponding to the solution of the system of constraints

Has vertices at (0, \frac{4}{3}), (0, 0) , (5, 0) and (3, 1)

Now evaluate the objective function at each vertex.

(0, 0) can be excluded as it will not give a maximum

(5, 0) → P = 5 + 0 = 5

(0, \frac{4}{3}) → 0 + 8 = 8

(3, 1) → 3 + 6(1) = 3 + 6 = 9 ← maximum value

Thus the maximum value is 9 when x = 3 and y = 1

7 0
3 years ago
Y = 2x^2 + 3<br> im looking for how to find the axis of symmetry
andre [41]

The axis of symmetry of the quadratic equation y = 2x^2 + 3 is x = 0

<h3>How to determine the axis of symmetry?</h3>

The equation is given as:

y = 2x^2 + 3

Differentiate the above equation with respect to x

y' = 4x + 0

This gives

y' = 4x

Set the equation to 0

4x = 0

Divide both sides by 4

x = 0

Hence, the axis of symmetry is x = 0

Read more about axis of symmetry at:

brainly.com/question/1349456

4 0
2 years ago
Read 2 more answers
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