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3 years ago

You are traveling 160 miles and it takes you 2.5 hours to get there what was your average speed

Mathematics

1 answer:

Anna35 [415]3 years ago

5 0

The speed is 64 miles per hour

Step-by-step explanation:

Lets define speed first.

"Speed is the distance per unit time"

Speed is denoted by s.

Given

Distance = d = 160 miles

Time = t = 2.5 hours

$Speed = \frac{Distance}{Time}\\s = \frac{d}{t}\\\\s = \frac{160}{2.5}\\\\s = 64\ miles\ per\ hour$

Hence,

The speed is 64 miles per hour

Keywords: Speed, distance

Learn more about speed at:

#LearnwithBrainly

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3 years ago

"What is the difference between a ratio and its related rate and unit rate?"

Vinil7 [7]

Answer:

Step-by-step explanation:

The ratio is the relationship of two numbers. ... A rate is a little bit different than the ratio, it is a special ratio. It is a comparison of measurements that have different units, like cents and grams. A unit rate is a rate with a denominator of 1.

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2 years ago

How do you translate the equation 4x-5=3(x+2) into a verbal sentence

elena55 [62]

Four times the quantity of x minus five is equal to three times the quantity of x plus two

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3 years ago

We take a milk carton from the refrigerator and put it on the table at room temperature. We assume that the temperature of the c

Kisachek [45]

We can solve this problem using separation of variables.

Then apply the initial conditions

EXPLANATION

We were given the first order differential equation

$\frac{dT}{dt}=k(T-a)$

We now separate the time and the temperature variables as follows,

$\frac{dT}{T-a}=kdt$

Integrating both sides of the differential equation, we obtain;

$ln(T-a)=kt +c$

This natural logarithmic equation can be rewritten as;

$T-a=e^{kt +c}$

Applying the laws of exponents, we obtain,

$T-a=e^{kt}\times e^{c}$

$T-a=e^{c}e^{kt}$

We were given the initial conditions,

$T(0)=4$

Let us apply this condition to obtain;

$4-20=e^{c}e^{k(0)}$

$-16=e^{c}$

Now our equation, becomes

$T-a=-16e^{kt}$

or

$T=a-16e^{kt}$

When we substitute a=20,
we obtain,

$T=20-16e^{kt}$

b) We were also given that,

$T(5)=8$

Let us apply this condition again to find k.

$8=20-16e^{5k}$

This implied

$-12=-16e^{5k}$

$\frac{-12}{-16}=e^{5k}$

$\frac{3}{4}=e^{5k}$

We take logarithm to base e of both sides,

$ln(\frac{3}{4})=5k$

This implies that,

$\frac{ln(\frac{3}{4})}{5}=k$

$k=-0.2877$

After 15 minutes, the temperature will be,

$T=20-16e^{-0.2877\times 15}$

$T=20-0.21376$

$T=19.786$

After 15 minutes, the temperature is approximately 20°C

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3 years ago

2x+3(2)=4<br> This is substitution. Please help I am stuck

Ber [7]

Answer:

x = -1

Step-by-step explanation:

2x + 3(2) = 4

2x + 6 = 4 Multiply 2 and 3 to get 6.

2x = -2 Subtract 6 from both sides to isolate 2x.

x = -1 Divide both sides by 2 to find x.

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3 years ago