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miskamm [114]
3 years ago
8

I’m really confused by this and need help?

Mathematics
2 answers:
AlekseyPX3 years ago
3 0

Divide 150 by 50 to get 3

lukranit [14]3 years ago
3 0

Fact family

150 ÷ 50 = 3

150 ÷ 3 = 50

50 x 3 = 150

Answer:

3

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How do I find the missing sides of this triangle by using trigonometry
Lemur [1.5K]

Step-by-step explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

You're given an angle, the adjacent side to that angle, and the hypotenuse.  So use cosine.

Cosine = Adjacent / Hypotenuse

cos 37° = 48 / x

Multiply both sides by x.

x cos 37° = 48

Divide both sides by cos 37°.

x = 48 / cos 37°

If desired, use a calculator to evaluate.

x ≈ 60.1

8 0
3 years ago
PLEASE HELP NEED ASAP
babymother [125]
What the formula?
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7 0
3 years ago
(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
3 years ago
4 - 2(x-4)/ 3= 3(2x+5)/2<br>pls answer fast​
adell [148]

Answer:

-21/22

Step-by-step explanation:

1.Apply fraction cross multiply

2. Simplify

3.Expand

4.Subtract 24 from both sides

5.simplify

6. Subtract 18x form both sides

7.Simpiify, then divide both sides by -22to get answer.

7 0
2 years ago
Given a triangle with perimeter 63 cm, one side of which is 21 cm, and one of the medians is perpendicular to one of its angle b
kodGreya [7K]

Answer:

The lengths of all sides of the triangle will be 21 cm, 21 cm, and 21 cm

Step-by-step explanation:

Given that the perimeter of the triangle = 63 cm

And the length of one side = 21 cm

and one of the medians is perpendicular to one of its angle bisectors

Since triangle has 3 sides,

Median = 63 ÷ 3 = 21

Therefore each side length = 21 cm

3 0
2 years ago
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