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Illusion [34]
3 years ago
7

Auto pistons at Wemming​ Chung's plant in Shanghai are produced in a forging​ process, and the diameter is a critical factor tha

t must be controlled. From sample sizes of 10 pistons produced each​ day, the mean and the range of this diameter have been as​ follows: Day Mean Bold x overbar ​(mm) Range R ​(mm) 1 156.9 4.4 2 155.2 4.4 3 153.6 4.3 4 157.5 4.8 5 158.6 4.5 (​a) What is the value of x double overbar​?
Business
1 answer:
evablogger [386]3 years ago
5 0

Answer:

The value of x double overbar​ is 156.36.

Explanation:

x double overbar​ = [156.9 + 155.2 + 153.6 + 157.5 + 158.6 ]/5

                             = 156.36

 Therefore, The value of x double overbar​ is 156.36.  

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Guy​ Ferrell, a student who lives in the country​ Paragon, observes that analysts are cutting their growth forecasts for the eco
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The correct answer to this open question is the following.

The statement, if​ true, that would explain the​ analysts' predictions would be "the Producer Price Index has been steadily increasing over the past few months."

That is what would have been the factor that supports the forecast. Although inflation has been constant at low levels, what changed was the Producer Price Index that is moving up. This factor could modify the results despite inflation is stable at this moment. When inflation is high, it directly affects the price of goods and the consumer.

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3 years ago
General mills offers three sizes of its popular cereal cheerios: 10-, 14-, and 18-ounce boxes, and they are priced at approximat
Marina86 [1]

General Mills sold three sizes of cereal cheerios at $2.99, $3.99, and $4.49 each. Selling tactic used by the company is psychology pricing. General Mills used this technique to encourage customers to respond on emotional levels rather than logical ones.

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4 0
3 years ago
If you sell 1,000 tickets at $50/ticket, 2,000 tickets at $60/ticket and 2,500 tickets at $65/ticket, what percentage of the rev
Charra [1.4K]
It’s 50% a ticket and it’s the right answer
4 0
3 years ago
8-12 REQUIRED RATE OF RETURN Suppose rRF 9%, rM 14%, and bi 1 3. a. What is ri, the required rate of return on Stock i? b. Now s
Nat2105 [25]

Answer:

a = 0.74 or 74%

b(1) = 0.75 or 75%

b(2) = 0.73 or 73%

c(1) = 1 or 1%

c(2) = 0.61 or 61%

Explanation:

The stock i has a risk free rate of 9% with a market return of 14% and beta of 13, using the formula we get,

ri = rRF + bi x (rM – rRF)

Where rRF=9/100=0.09

bi =13

rm =14/100=0.14

Putting the values into the formula

= 0.09 + 13 x (0.14 – 0.09)

= 0.74 or 74%

b. (1)

Ri = rRF + bi x (rM – rRF)= 0.10 + 13 x (0.14 – 0.09)= 0.75 or 75%

Here the slope of SML remains constant, meaning the market risk premium will not change. As a result, the required return will increase by 1%.

b(2)

Ri = rRF + bi x (rM – rRF)= 0.08 + 13 X (0.14 – 0.09)= 0.73 or 73%

Here, the slope of SML remains constant, meaning the market risk premium will not change. As a result the required return will decrease by 1%.

c. (1)

Ri = rRF + bi x (rM – rRF)= 0.09 + 13 x (0.16 – 0.09)= 1 or 1%

Here, the slope of SML does not remain constant, meaning the market risk premium will change. As a result, the required return will increase.

(2)Ri = rRF + bi x (rM – rRF)= 0.09 + 13 x (0.13 – 0.09)=0.61 or 61%

Here, the slope of SML remains constant, meaning the market risk premium will not change. As a result, the required return will decrease by 13%.

3 0
3 years ago
A well known bank stores enough money during the weekends to satisfy its customers needs. The expected average withdrawal during
Alexxx [7]

Answer:

The mean withdraw has increased during weekend.

Explanation:

Assume that the withdraw amounts are normal distributed. To test whether the mean withdrawal has increased during weekends, we take a z-test. The z-test is possible because the observed sample (weekend transactions) is greater than 30.

The null hypothesis (H_{0}) is when the mean withdrawal is greater than 550. The alternative hypothesis (H_{A}) is when the mean withdrawal is equal to 550 or smaller. At an alpha of 0.05% is selected with a two-tailed test, , there is 0.025% of the samples in each tail, and the alpha has a critical value of 1.96 or -1.96. If the z-value is greater than 1.96 or less than -1.96, the null hypothesis is rejected.

z-value = (600-550) / 70 / 36^(1/2) = 0.1190

At α=0.05, the z-value < 1.96 and > -1.96, the null hypothesis is not rejected. Therefore, the mean withdraw has increased during weekend.

3 0
3 years ago
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