Find the slope of the line whose equation is 5y = x - 3. -3 -3/5 1/5 5

1 answer:

5 0

The slope of the line whose equation follows the point-slope form (y=mx + b) is m. Transforming the equation 5y = x - 3 into the point-slope form by dividing the whole equation by 5 results to $y = \frac{1}{5} (x) - \frac{3}{5}$ . The slope, m, is 1/5.

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Plz help meh... i need it asap

kap26 [50]

Answer:

y=x

Step-by-step explanation:

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1 year ago

A student is asked to find a polynomial f(x) of degree four with the zeros 2, -3, 0, and -7. What factors would the student mult

lord [1]

Answer:

(x-2), (x+3),x and (x + 7)

Step-by-step explanation:

Here, the zeros of the polynomial are 2, -3, 0 and -7.

Let’s consider a case of a quadratic equation where x = 5 is a solution. This means that x + 5 is a factor of that quadratic equation.

Now, let’s apply same approach to this polynomial. If x = 2 is a solution, then x -2 is a factor. If x = -3, then, x + 3 is a factor. If x = 0, this means x itself is a solution and lastly, if x = -7 is a solution, that means x + 7 is a factor.

Thus, the factors to multiply together are; (x-2), (x+3),x and (x + 7)

4 0

2 years ago

Length of a rectangle is four times its width. If the perimeter is 100 m, what is the area in square cm?

melisa1 [442]

Set the width to be x. Thus, the length is 4x.

The perimeter is 2(x+4x)=100, so x=10.

Plugging in x=10, you get that 4x=40.

So, the area of the rectangle is 400 $m^2$ .