Answer:
B
Step-by-step explanation:
5a^2 - 44 = 81 Add 44 to both sides
5a^2 = 81 + 44 Collect like terms
5a^2 = 125 Divide both sides by 5
a^2 = 125/5
a^2 = 25 Take the square root of both sides
√a^2 = √25
a = +5
a = -5
The answer is B
These are the two rules for when a and b are positive numbers.
a + b = b + a
a - b ≠ b -a
a - b = -b + a
For example:
5.71 + 2.84 = 2.84 + 5.71
8.55 = 8.55
5.71 - 2.84 ≠ 2.84 - 5.71
2.87 ≠ -2.87
5.71 - 2.84 = -2.84 + 5.71
2.87 = 2.87
These are the rules for when a and b are negative numbers.
a + b = b + a
a - b = b + a
For example,
-6.2 + (-3.96) = -3.96 + (-6.2)
-6.2 - 3.96 = -3.96 - 6.2
-10.16 = -10.16
-6.2 - (3.96) = -3.96 + (-6.2)
-10.16 = -10.16
Also, if a is a positive number, while b is a negative number, we see these rules:
a + b = a - b
a - b = a + b
For example,
5.71 + (-6.2) = 5.71 - 6.2
-0.49 = -0.49
5.71 - (-6.2) = 5.71 + 6.2
11.91 = 11.91
Also, if a is a negative number while b is a positive number, then these rules will apply:
a + b = b - a
a - b = -b - a
For example,
-3.96 + 2.84 = 2.84 - 3.96
-1.12 = <span>-1.12
</span>
-3.96 - 2.84 = -2.84 - 3.96
-6.8 = -6.8
I hope this helps! :)
Answer:
51,51 and 78
Step-by-step explanation:
3x+9=4x-5
3x=4x-14
-x=-14
x=14
<h2>~<u>Solution</u> :-</h2>
Here, it is given that the bag contains 25 paise coins and 50 paise coins in which, 25 paise coins are 6 times than that of 50 paise coins. Also, the total money in the bag is Rs. 6.
- Hence, we can see that, here, we have been given the linear equation be;
Let the number of coins of 50 paise will be $ x $ and the number of coins of 25 paise will be $ 6x $ as given. . .
Hence,
- Hence, the number of 50 paise coins will be <u>2</u>. And, 6 times of two be;
- Hence, the number of 25 paise coins will be <u>12</u>.
