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Sladkaya [172]
2 years ago
6

SOMEONE PLEASE HELP ITS WORTH 90 POINTS

Mathematics
1 answer:
motikmotik2 years ago
3 0

Answer:

Step-by-step explanation:

The two x angles on the right are supplementary which means they add up to 180 degrees

5x + 12 + 7x - 24 = 180

12x - 12 = 180

12x = 192

x = 192/12

x = 18

5x + 12 and y are corresponding angles and are therefore equal

5(18) + 12 = 90 + 12 = 102

Therefore y = 102

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Please help me with this one
ruslelena [56]

Answer:

3.9375

Step-by-step explanation:

3 0
3 years ago
HELP PLS HERE IS IT NEED IT
Zielflug [23.3K]

Step-by-step explanation:

Total students = 35

Probability that a student earns A B or C = 5 + 10 + 15 = 30

35/30 = 7/6

3 0
3 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
2 years ago
What is the answer? ​
Dimas [21]

Answer:

10

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is 1/7+ x = 2/3x
navik [9.2K]
1/7 + x = 2/3x
1/7 = 2/3x-x
1/7 = 2/3x - 1x
1/7 = -1/3x
-3/7 = x
6 0
3 years ago
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