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Helga [31]
4 years ago
7

A student earned a grade of 80% on a math test that had 20 problems . How many did he get right?

Mathematics
2 answers:
JulijaS [17]4 years ago
7 0
80/100·20=8/10·20=8·2=16 (problems he got right)

<em>Answer:16</em>
shutvik [7]4 years ago
6 0
Multiply 80 and 20 and divide by 100 and get answer of 16.
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What percent of 225 is 180
Marysya12 [62]
Hello! To solve this problem, we should do 180/225. When you do that, you get 0.8. But then, you must multiply by 100 to get your percentage. When you do that, the product should be 80. 180 is 80% of 225.
8 0
3 years ago
Read 2 more answers
The nth term of a sequence is 3n2-1
maksim [4K]

Answer: The common number is 26.

Step-by-step explanation:

We know that the n-th term of a sequence is:

aₙ = 3*n^2 - 1

And the n-th term of another sequence is:

bₙ = 30 - n^2

Remember that in a sequence n is always an integer number.

We want to find a number that belongs to both sequences, then we want to find a pair of integers x and n, such that:

aₙ = bₓ

This is:

3*n^2 - 1 = 30 - x^2

Let's isolate one of the variables, i will isolate n.

3*n^2 = 30 - x^2 + 1 = 31 - x^2

n^2 = (31 - x^2)/3

n = √( (31 - x^2)/3)

Now we can try with different integer values of x, and see if n is also an integer.

if x = 1

n = √( (31 - 1^2)/3) = √10

We know that √10 is not an integer, so we need to try with another value of x.

if x = 2:

n = √( (31 - x^2)/3) = √(27/3) = √9 = 3

Then if we have x= 2, n is also an integer, n = 3.

Then we have:

a₃ = b₂

The common number between both sequences is:

a₃ = 3*(3)^2 - 1 = 26

b₂ = 30 - 2^2 = 26

6 0
3 years ago
I need help with this!
Vadim26 [7]
92749363929202082973
5 0
4 years ago
This figure consists of a rectangle and a quarter circle.
poizon [28]

The perimeter of the figure is 50.56 cm.

Solution:

Radius of the quarter of a circle = 8 cm

Perimeter of the quarter circle = \frac{1}{4} 2\pi r

                                                  $=\frac{1}{4} \times 2  \times 3.14  \times 8

                                                  = 12.56 cm

In figure, one side of the quarter circle is merged with rectangle, so remove one radius from the perimeter of the quarter circle.

Perimeter of the given quarter circle = 12.56 cm – one radius

                                                             = 12.56 cm – 8 cm

                                                             = 4.56 cm

Perimeter of the rectangle given = (17 – 8) cm + 10 cm + 17 cm + 10 cm

                                                       = 9 cm + 10 cm + 17 cm + 10 cm

                                                       = 46 cm

Perimeter of the given figure = 4.56 cm + 46 cm

                                                = 50.56 cm

Hence the perimeter of the figure is 50.56 cm.

6 0
4 years ago
X2+Y2=25
Fofino [41]
x^{2} + y^{2} =25 is equation of circle which have radius equal 5 and center in (0,0) point

8 0
3 years ago
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