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insens350 [35]
3 years ago
7

Approximate 221 ( square root) to the nearest hundredths.

Mathematics
1 answer:
schepotkina [342]3 years ago
6 0
The answer would be C
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Please please please help me
Leviafan [203]
The correct answer is 17 what i did was plug in 17 where ever you see x so x2 would be 17x2 an then plus the 5 gives u 39 3x 17x3=51 51+10=61 now add the totals 61 plus 39 gives u 100
8 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through these two points? (-3, 2) (4, 2)
Alik [6]

Answer: 0

Step-by-step explanation:

To find slope, I found that an easy way is the equation y2 - y1 over (divided by) x2 - x1

so for this, it would be:

\frac{2 - 2}{4-(-3)}

which is 0/7

0 divided by 7 is 0, so there is your answer

6 0
3 years ago
A coin is tossed twice. What is the probability of getting a tail in the first toss and a tail in the second toss?
skelet666 [1.2K]

Answer:

<h2>1/4 Chances</h2><h2>25% Chances</h2><h2>0.25 Chances (out of 1)</h2>

Step-by-step explanation:

Two methods to answer the question.

Here are presented to show the advantage in using the product rule given above.

<h2>Method 1:Using the sample space</h2>

The sample space S of the experiment of tossing a coin twice is given by the tree diagram shown below

The first toss gives two possible outcomes: T or H ( in blue)

The second toss gives two possible outcomes: T or H (in red)

From the three diagrams, we can deduce the sample space S set as follows

          S={(H,H),(H,T),(T,H),(T,T)}

with n(S)=4 where n(S) is the number of elements in the set S

tree diagram in tossing a coin twice

The event E : " tossing a coin twice and getting two tails " as a set is given by

          E={(T,T)}

with n(E)=1 where n(E) is the number of elements in the set E

Use the classical probability formula to find P(E) as:

          P(E)=n(E)n(S)=14

<h2>Method 2: Use the product rule of two independent event</h2>

Event E " tossing a coin twice and getting a tail in each toss " may be considered as two events

Event A " toss a coin once and get a tail " and event B "toss the coin a second time and get a tail "

with the probabilities of each event A and B given by

          P(A)=12 and P(B)=12

Event E occurring may now be considered as events A and B occurring. Events A and B are independent and therefore the product rule may be used as follows

        P(E)=P(A and B)=P(A∩B)=P(A)⋅P(B)=12⋅12=14

NOTE If you toss a coin a large number of times, the sample space will have a large number of elements and therefore method 2 is much more practical to use than method 1 where you have a large number of outcomes.

We now present more examples and questions on how the product rule of independent events is used to solve probability questions.

8 0
3 years ago
Read 2 more answers
Jayson said, "I am thinking of two fractions that when added have a sum of 1." Which fractions could Jayson have been thinking a
viva [34]

Answer:

3/6 and 3/6

thanks mate

5 0
3 years ago
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A computer was on sale for 3/4 of the original price. If the original price was $1,600 what was the sale price?
Gre4nikov [31]

Answer:

$1200

Step-by-step explanation:

3/4 of 1600 is 1200

7 0
3 years ago
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