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Korolek [52]
3 years ago
6

In a bilateral monopoly with one buyer and one seller, the monopoly power of the seller and the monopsony power of the buyer ten

d to: counter-act one another. reinforce one another. favor the buyer. favor the seller.
Business
1 answer:
scoray [572]3 years ago
6 0

Answer:

counter-act one another.

Explanation:

As  a bilateral monopoly has one buyer and one seller, the buyer wants to pay the lower price possible and the seller wants to charge a high price. So, they have opposite goals and they have to negotiate considering the power each one has and find an agreement in which both win. According to this, the answer is that in a bilateral monopoly with one buyer and one seller, the monopoly power of the seller and the monopsony power of the buyer tend to counter-act one another as their positions are in conflict and they have to find a middle point to get to an agreement.

The other options are not right because their goals are in conflict so they don't support the idea of the other party and both parties have a relative bargaining power and because of that, the monopoly power of the parties does not favor the buyer or the seller.

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If the world's population increased exponentially from 5.937 billion in 1998 to 6.771 billion in 2008 and continued to increase
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Answer:

The world's population would have been 7.1137 billion in 2012, and this is 0.0437 billion (i.e. 7.1137 - 7.07 = 0.0437) higher compared to the population reference bureau estimate of 7.07 billion in July 2012.

Explanation:

This can be computed using the following exponential formula:

P(t) = P(0)a^t ............................ (1)

Where;

P(t) = World population in year t.

P(0) = World population in year 0 which is 1998 = 5.937 billion

a = base = ?

t = number of years

Substituting the value into equation (1), we have:

P(t) = 5.937 * a^t .......................................... (2)

Since we have 10 years from 1998 to 2008 (i.e. 2008 - 1998 = 10), we have:

P(t) = P(10) = World population in 2008 = 6.771 billion

t = 10

Substituting the value into equation (2) and solve for a, we have:

6.771 = 5.937 * a^10

a^10 = 6.771 / 5.937

a^10 = 1.1405

a = \sqrt[10]{1.405}

a = 1.013

Since we have 14 years from 1998 to 2012 (i.e. 2012 - 1998 = 14), we now have:

P(t) = P(14) = World population in 2012 = ?

P(0) = World population in year 0 which is 1998 = 5.937 billion

a = 1.013 as already calculated above

t = 14

Substituting the value into equation (1), we have:

P(14) = 5.937 * 1.013^14

P(14) = 5.937 * 1.192

P(14) = 7.1137 billion

Therefore, the world's population would have been 7.1137 billion in 2012, and this is 0.0437 billion (i.e. 7.1137 - 7.07 = 0.0437) higher compared to the population reference bureau estimate of 7.07 billion in july 2012.

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Answer:

D) short-run fluctuations in output and employment

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