3x$2.49+2x$3.19+4x$4.99=$33.81
Y(initial) = 9
V(initial) = 168
V(final) = 0
g(accel-grav) = 32 (in feet per second
squared)
Use the following equation:
V(final) = V(initial) + a(t)
Since this object is moving straight up and
down, a = -32
Enter the knowns into the equation
0 = 168 - 32t
32t = 168
t = 168/9.8
t = 5.25
Now that you know the time it takes to
reach it's maximum, use the general
kinematics equation to solve for final
distance:
y(final) = y(initial) + V(initial)(t) + (1/2)a
(t²)
y(final) = 9 + 168(5.25) + (1/2)(-32)
(5.25²)
= 9 + 882 - 441
= 450 feet
None of those is. The expression 4 In x + In 3 – In r
is equivalent to the epression <em>ln( 3x⁴ / r)</em> .
Answer:
slope1 : 7, slope 2 = 3 solution: (2,5)
Step-by-step explanation:
I simplify some steps
pair 1: x1 0 2
y1 -9 5 ........ -9, y1 intercept
pair 2: x2 0 2
y2 -1 5 ........ -1, y2 interept
2 pairs meet at (2,5)
y=7x-9 ......A
y=3x-1 ......B
A-B 0=4x-8
4x=8
x=2
y=5
slope 1=( y2-y1) / (x2-x1) = (5- -9)/(2-0) = 14/2 =7
slope 2 = (5 - -1) / (2 - 0) = 6/2 = 3
Answer:to Let f(t) = 6, g(t) = −5t, and h(t) = 2t2
Step-by-step explanation:
