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BabaBlast [244]
3 years ago
12

What are all the factors of 43?

Mathematics
2 answers:
Tems11 [23]3 years ago
7 0

Answer: Factors of 43: 1, 43

Step-by-step explanation:

jenyasd209 [6]3 years ago
3 0

Answer:

1 and 43

Step-by-step explanation:

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How do you do this??
astra-53 [7]

welll...you have there written just one relationship...it is berween 280 and 4 hours...you have to figure out speed:

280 \div 4 = 70

it is speed per hour

then you just connect time and speed:

  1. 140 - 2
  2. 280 - 4
  3. 350 - 5
  4. 420 - 6
  5. 560 - 8
  6. 700 - 10
6 0
3 years ago
20 This spinner will be spun twice. What is the probability of
natali 33 [55]

Answer: the probability is 0.25

Step-by-step explanation:

We have 10 numbers:

0, 1, 2, 3, 4, 5, 6, 7, 8, 9

Of those, the odd ones are:

1, 3, 5, 7, 9

So we have 5 odd numbers.

The probability that the outcome is an odd number is equal to the number of odd numbers divided the total number of numbers:

p = 5/10 = 0.5

For the second spin the probability is the same, p = 5/10, because the first outcome does not affect the results of the second spin.

The probability of spining an odd number both times, then is the joint probability for two times this same event:

P = (5/10)(5/10) = 0.5*0.5 = 0.25

or 25% in percent form

3 0
3 years ago
#1-11<br><br> 20 points!!!!!
lesya [120]

Answer:

Step-by-step explanation:

1. 30

2. 23

3. 8

4.52

5.144

6.40

7. 210

8. 144

9. 135

10. 105

11. 2(207)

6 0
3 years ago
4(4b-8)-3/8<br> Please help i have no idea what to do
Ksivusya [100]

Answer:

4(4b - 8) -  \frac{3}{8}  \\ 16b - 32 -  \frac{3}{4}  \\ \frac{64b - 128 - 3}{8}  \\  \frac{64b - 131}{8}

hope this will help you

7 0
2 years ago
Prove the following statement.
gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form 2k+1 where k\in \mathbb{Z}. Consider the following cases.

Case 1. If k is even we have: (2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1.

If we denote by m=2s^2+2 we have that (2k+1)^{2}=8m+1.

Case 2. if k is odd we have: (2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1.

If we denote by m=2s^{2}+24s+1 we have that (2k+1)^{2}=8m+1

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

6 0
3 years ago
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