Question

The longest side of an acute isosceles triangle is 8 centimeters. Rounded to the nearest tenth , what is the smallest possible length of one of the two congruent sides?

Answer 1

Let
a---------> length of one of the two congruent sides of the triangle

we know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
so
(a+a) > 8
2a > 8
a> 4
Rounded to the nearest tenth, the smallest possible length of a is 4.1

the answer is
4.1 units